Solve sin(45°)

Step-by-step solution

1. In a $45$-$45$-$90$ isosceles right triangle, opposite leg / hypotenuse = $\frac{1}{\sqrt{2}}$.

2. Rationalise: $\frac{1}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}$.

3. On the unit circle at $45°$ both x and y equal $\frac{\sqrt{2}}{2}$ — confirms the answer.