Calculus · real student question

Find the limit of x squared minus 4 as x approaches positive infinity.

Question

Evaluate the limit

limx(x24)\lim_{x\to\infty}\left(x^2-4\right)

Step-by-step solution

  1. Compare the two terms. As xx grows, x2x^2 grows without bound while 4-4 never changes. In any sum, the term with the highest degree eventually dominates, so the limit is governed by x2x^2 alone.

  2. Evaluate the dominant term. xx\to\infty gives x2+x^2\to+\infty (squaring a large positive number makes it larger still).

  3. Subtract the constant. Removing a fixed 44 from an unbounded quantity leaves it unbounded:

    x24+x^2-4\to+\infty

    The shift only moves the graph down by 44 units; it cannot cap its growth.

  4. Verify numerically. At x=10x=10: 9696. At x=100x=100: 99969996. At x=1000x=1000: 999996999996. Each step of ten in xx multiplies the output by roughly 100100.

  5. Interpret the answer honestly. We write

    limx(x24)=+\lim_{x\to\infty}(x^2-4)=+\infty

    but ++\infty is not a number: the correct wording is that the limit does not exist as a finite value, and the function diverges to ++\infty. Note also that limx(x24)=+\lim_{x\to-\infty}(x^2-4)=+\infty too, since squaring removes the sign.

Answer

limx(x24)=+\lim_{x\to\infty}\left(x^2-4\right)=+\infty

Need to solve a different problem like this? Open the solver →