Algebra · real student question

Solve 1 over 2.7421 equals 1 over 3.3 plus 1 over x, for x.

Question

Solve for xx:

12.7421=13.3+1x\frac{1}{2.7421}=\frac{1}{3.3}+\frac1x

Step-by-step solution

  1. Isolate 1x\frac1x.

    1x=12.742113.3\frac1x=\frac{1}{2.7421}-\frac{1}{3.3}

    Here 2.7421<3.32.7421<3.3, so this difference is positive and xx will be positive — the combination sits below both parts, as a parallel/reciprocal combination should.

  2. Combine the two fractions in one move. The identity 1a1b=baab\frac1a-\frac1b=\frac{b-a}{ab} avoids computing two decimals separately and subtracting:

    1x=3.32.74212.7421×3.3\frac1x=\frac{3.3-2.7421}{2.7421\times 3.3}

  3. Compute the numerator and the denominator carefully.

    3.32.7421=0.5579,2.7421×3.3=9.048933.3-2.7421=0.5579,\qquad 2.7421\times 3.3=9.04893

    That product is worth double-checking: 2.7421×3=8.22632.7421\times 3=8.2263 and 2.7421×0.3=0.822632.7421\times 0.3=0.82263, and 8.2263+0.82263=9.048938.2263+0.82263=9.04893. A frequently seen slip records it as 9.049939.04993, which shifts the final answer in the fourth significant figure.

  4. Invert the quotient.

    x=9.048930.5579=16.21963x=\frac{9.04893}{0.5579}=16.21963

    Using the erroneous 9.049939.04993 instead would give 16.221416.2214 — close, but wrong past three decimals.

  5. Verify by substitution. 13.3=0.3030303\frac{1}{3.3}=0.3030303 and 116.21963=0.0616537\frac{1}{16.21963}=0.0616537; their sum is 0.36468400.3646840, which equals 12.7421=0.3646840\frac{1}{2.7421}=0.3646840 ✓. So x16.2196x\approx 16.2196.

Answer

x=2.7421×3.33.32.7421=9.048930.557916.2196x=\frac{2.7421\times 3.3}{3.3-2.7421}=\frac{9.04893}{0.5579}\approx 16.2196

Need to solve a different problem like this? Open the solver →