Problem∫2sinx dx\int 2\sin x \, dx∫2sinxdxStep-by-step solution把常數提出來：2∫sinx dx2 \int \sin x \, dx2∫sinxdx。∫sinx dx=−cosx+C\int \sin x \, dx = -\cos x + C∫sinxdx=−cosx+C。相乘：−2cosx+C-2\cos x + C−2cosx+C。Answer−2cos(x)+C-2\cos(x) + C−2cos(x)+CWant to solve a different problem? Open the integral solver →Related worked examples/solve/calculus/integral-of-sin-x-dx