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Algebra · real student question

解 5.28 × (3.64x − 9.71) + (x + 8.12)/4.79 = −(9.46x − 2.53)/7.01,x 取到小數點後兩位。

Question

解下列方程式

5.28(3.64x−9.71)+x+8.124.79=−9.46x−2.537.015.28(3.64x-9.71)+\frac{x+8.12}{4.79}=-\frac{9.46x-2.53}{7.01}

xx 取到小數點後兩位。

Step-by-step solution

  1. 先展開括號乘積。 小數要精確相乘,一路保留完整位數到最後——太早四捨五入正是這類題目最主要的錯誤來源:

    5.28×3.64=19.2192,5.28×9.71=51.26885.28\times 3.64=19.2192,\qquad 5.28\times 9.71=51.2688

    所以第一項是 19.2192x−51.268819.2192x-51.2688。

  2. 把每個分式拆成 x 的部分與常數部分。 把和逐項去除,分式就變成尋常的小數係數:

    x+8.124.79=14.79x+8.124.79=0.208768x+1.695198\frac{x+8.12}{4.79}=\frac{1}{4.79}x+\frac{8.12}{4.79}=0.208768x+1.695198

    −9.46x−2.537.01=−9.467.01x+2.537.01=−1.349501x+0.360913-\frac{9.46x-2.53}{7.01}=-\frac{9.46}{7.01}x+\frac{2.53}{7.01}=-1.349501x+0.360913

  3. 把左邊整理起來。

    19.2192x+0.208768x−51.2688+1.695198=19.427968x−49.57360219.2192x+0.208768x-51.2688+1.695198=19.427968x-49.573602

  4. 把 x 項全移到左邊、常數全移到右邊。

    19.427968x+1.349501x=0.360913+49.57360219.427968x+1.349501x=0.360913+49.573602

    20.777469x=49.93451520.777469x=49.934515

  5. 相除並四捨五入。

    x=49.93451520.777469=2.403301≈2.40x=\frac{49.934515}{20.777469}=2.403301\approx 2.40

    x=2.40\boxed{x=2.40}

  6. 用未四捨五入的值代入檢查。 取 x=2.403301x=2.403301:左式是 5.28(8.7480−9.71)+10.52334.79=−5.0793+2.1969=−2.88235.28(8.7480-9.71)+\tfrac{10.5233}{4.79}=-5.0793+2.1969=-2.8823,右式是 −22.7352−2.537.01=−20.20527.01=−2.8823-\tfrac{22.7352-2.53}{7.01}=-\tfrac{20.2052}{7.01}=-2.8823。兩邊吻合到小數點後四位,確認了這個解。

Answer

x≈2.40x\approx 2.40

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