Problema2+b2=c2, a=7, b=24a^2 + b^2 = c^2,\ a=7,\ b=24a2+b2=c2, a=7, b=24分步解答以 a=7a = 7a=7、b=24b = 24b=24 套用 a2+b2=c2a^2 + b^2 = c^2a2+b2=c2。72+242=49+576=6257^2 + 24^2 = 49 + 576 = 62572+242=49+576=625。c=625=25c = \sqrt{625} = 25c=625=25。(7,24,25)(7, 24, 25)(7,24,25) 又是另一组本原勾股数 —— 把它们记下来;它们常出现在标准化考试中。答案c=25c = 25c=25想解其他题?打开 pythagorean-theorem 求解器 →相关例题/solve/geometry/triangle-3-4-5/solve/geometry/triangle-5-12-13/solve/geometry/triangle-8-15-17