Solve right triangle with legs 8 and 15

Problem

$a^2 + b^2 = c^2,\ a=8,\ b=15$

Step-by-step solution

Identify the legs: $a = 8$ , $b = 15$ .
Apply Pythagorean theorem: $a^2 + b^2 = c^2$ .
Substitute: $8^2 + 15^2 = 64 + 225 = 289$ .
Take positive square root: $c = \sqrt{289} = 17$ .
$(8, 15, 17)$ is another primitive Pythagorean triple — coprime triple not generated by scaling.

Answer

$c = 17$

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