geometry · worked example

Solve समलंब के समांतर भुजाएँ 3 और 7, ऊँचाई 5 — A = 25

Method: समलंब का क्षेत्रफल. Verified step-by-step solution with our free AI math solver.
Problem

A=12(b1+b2)h, b1=3, b2=7, h=5A = \tfrac{1}{2}(b_1+b_2)h,\ b_1=3,\ b_2=7,\ h=5

Step-by-step solution

  1. A=12(b1+b2)hA = \tfrac{1}{2}(b_1 + b_2) h लागू करें।

  2. प्रतिस्थापित करें: A=12(3+7)(5)=12(10)(5)=25A = \tfrac{1}{2}(3 + 7)(5) = \tfrac{1}{2}(10)(5) = 25

Answer

A=25A = 25

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