geometry · worked example

Solve 5 और 8 आधार तथा 4 ऊँचाई वाला समलंब चतुर्भुज — A = 26

Problem

$A = \tfrac{1}{2}(b_1 + b_2) h,\ b_1=5,\ b_2=8,\ h=4$

Step-by-step solution

समलंब चतुर्भुज का क्षेत्रफल: $A = \tfrac{1}{2}(b_1 + b_2) h$ ।
$b_1 = 5$ , $b_2 = 8$ , $h = 4$ प्रतिस्थापित करें: $A = \tfrac{1}{2}(5 + 8)(4) = \tfrac{1}{2}(13)(4)$ ।
सरल करें: $A = 26$ ।

Answer

$A = 26$

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