ProblemV=13πr2h, r=3, h=7V = \tfrac{1}{3}\pi r^2 h,\ r=3,\ h=7V=31πr2h, r=3, h=7Step-by-step solution圓錐體積:V=13πr2hV = \tfrac{1}{3}\pi r^2 hV=31πr2h。代入:V=13π⋅9⋅7=21π≈65.97V = \tfrac{1}{3}\pi \cdot 9 \cdot 7 = 21\pi \approx 65.97V=31π⋅9⋅7=21π≈65.97。注意係數 1/3 — 圓錐是同底同高圓柱的三分之一。AnswerV=21π≈65.97V = 21\pi \approx 65.97V=21π≈65.97Want to solve a different problem? Open the volume solver →Related worked examples/solve/geometry/volume-cylinder-radius-3-height-10/solve/geometry/volume-sphere-radius-5