Problem3x2+7x+23x^2 + 7x + 23x2+7x+2Step-by-step solutionac=3⋅2=6ac = 3 \cdot 2 = 6ac=3⋅2=6。找出兩個數,相乘為 666、相加為 777:(1,6)(1, 6)(1,6)。拆分中間項:3x2+x+6x+23x^2 + x + 6x + 23x2+x+6x+2。用分組法分解:x(3x+1)+2(3x+1)=(3x+1)(x+2)x(3x + 1) + 2(3x + 1) = (3x + 1)(x + 2)x(3x+1)+2(3x+1)=(3x+1)(x+2)。Answer(3x+1)(x+2)(3x + 1)(x + 2)(3x+1)(x+2)Want to solve a different problem? Open the factoring solver →Related worked examples/solve/algebra/factor-2x-squared-plus-5x-plus-3Read more/blog/factoring-polynomials-step-by-step