Problem∫2x dx\int 2x \, dx∫2xdx分步解答把常数提出来:∫2x dx=2∫x dx\int 2x \, dx = 2 \int x \, dx∫2xdx=2∫xdx。套用幂法则:∫x dx=x22+C\int x \, dx = \frac{x^2}{2} + C∫xdx=2x2+C。相乘:2⋅x22=x22 \cdot \frac{x^2}{2} = x^22⋅2x2=x2。加上积分常数:x2+Cx^2 + Cx2+C。答案x2+Cx^2 + Cx2+C想解其他题?打开 integral 求解器 →相关例题/solve/calculus/integral-of-x2-dx