Problem∫x2 dx\int x^2 \, dx∫x2dx分步解答应用积分的幂次法则:∫xn dx=xn+1n+1+C\int x^n \, dx = \frac{x^{n+1}}{n+1} + C∫xndx=n+1xn+1+C(在 n≠−1n \neq -1n=−1 时成立)。当 n=2n = 2n=2 时:∫x2 dx=x2+12+1+C=x33+C\int x^2 \, dx = \frac{x^{2+1}}{2+1} + C = \frac{x^3}{3} + C∫x2dx=2+1x2+1+C=3x3+C。务必加上积分常数 CCC——不定积分表示一族原函数。答案x33+C\frac{x^3}{3} + C3x3+C想解其他题?打开 integral 求解器 →相关例题/solve/calculus/integral-of-sin-x-dx