Problemddx(3x2+4x−1)\frac{d}{dx}(3x^2 + 4x - 1)dxd(3x2+4x−1)分步解答使用加法法则逐项微分。ddx(3x2)=6x\frac{d}{dx}(3x^2) = 6xdxd(3x2)=6x(提出常数,使用幂函数微分法则)。ddx(4x)=4\frac{d}{dx}(4x) = 4dxd(4x)=4。ddx(−1)=0\frac{d}{dx}(-1) = 0dxd(−1)=0(常数)。合并:6x+46x + 46x+4。答案6x+46x + 46x+4想解其他题?打开 derivative 求解器 →相关例题/solve/calculus/derivative-of-x3-plus-2x/solve/calculus/derivative-of-2x-plus-3