Problemx2+3x−10=0x^2 + 3x - 10 = 0x2+3x−10=0分步解答找出两个相乘为 −10-10−10、相加为 333 的数。配对 (5,−2)(5, -2)(5,−2):5⋅(−2)=−105 \cdot (-2) = -105⋅(−2)=−10 ✓,5+(−2)=35 + (-2) = 35+(−2)=3 ✓。因式分解:(x+5)(x−2)=0(x + 5)(x - 2) = 0(x+5)(x−2)=0。令每个因式为零:x=−5x = -5x=−5 或 x=2x = 2x=2。答案x=−5orx=2x = -5 \quad \text{or} \quad x = 2x=−5orx=2想解其他题?打开 quadratic 求解器 →相关例题/solve/algebra/x2-plus-5x-plus-6/solve/algebra/x2-plus-x-minus-6