Problem4x2−9=04x^2 - 9 = 04x2−9=0分步解答辨认为平方差:4x2=(2x)24x^2 = (2x)^24x2=(2x)2 且 9=329 = 3^29=32。因式分解:(2x−3)(2x+3)=0(2x - 3)(2x + 3) = 0(2x−3)(2x+3)=0。令每个因式为零:2x−3=02x - 3 = 02x−3=0 或 2x+3=02x + 3 = 02x+3=0。求解:x=32x = \tfrac{3}{2}x=23 或 x=−32x = -\tfrac{3}{2}x=−23。答案x=32orx=−32x = \tfrac{3}{2} \quad \text{or} \quad x = -\tfrac{3}{2}x=23orx=−23想解其他题?打开 quadratic 求解器 →相关例题/solve/algebra/x2-minus-9/solve/algebra/x2-minus-25