Algebra · real student question

Solve the inequality -4x + 6 <= 18.

Question

Solve

4x+618-4x+6\le 18

Step-by-step solution

  1. Move the constant first. Subtract 66 from both sides. Adding or subtracting never affects the direction of an inequality:

    4x12-4x\le 12

  2. Divide by 4-4 and reverse the sign. Dividing by a negative number flips \le into \ge:

    x124=3x\ge\frac{12}{-4}=-3

    Why the flip happens: multiplying by a negative reflects the number line, so the order of any two numbers is reversed. For instance 232\le 3 but 23-2\ge -3.

  3. Alternative route that avoids the flip. You can instead add 4x4x to both sides and subtract 1818:

    6184x    124x    3x6-18\le 4x\;\Longrightarrow\;-12\le 4x\;\Longrightarrow\;-3\le x

    which is the same statement written the other way round. Keeping the variable coefficient positive is a reliable way to sidestep sign errors.

  4. Check a value on each side of 3-3. At x=0x=0: 4(0)+6=618-4(0)+6=6\le 18 \checkmark (should be in the solution set). At x=10x=-10: 40+6=46≰1840+6=46\not\le 18 \checkmark (should be out). At the boundary x=3x=-3: 12+6=181812+6=18\le 18 \checkmark, so the endpoint is included.

Answer

x3,i.e. [3,)x\ge -3,\qquad\text{i.e. }[-3,\infty)

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