Algebra · real student question

Find the value of C = x² − 8xy + 16y² given that x − 4y = 5.

Question

Find the value of

C=x28xy+16y2C = x^2 - 8xy + 16y^2

given that x4y=5x - 4y = 5.

Step-by-step solution

  1. Notice that the given condition does not determine x and y separately. One equation in two unknowns has infinitely many solutions, so the expression must be arranged to depend only on the combination x4yx - 4y. That is a strong hint to look for a perfect square.

  2. Match the expression to the perfect-square pattern. The identity is

    (AB)2=A22AB+B2(A - B)^2 = A^2 - 2AB + B^2

    Here A2=x2A^2 = x^2 gives A=xA = x, and B2=16y2B^2 = 16y^2 gives B=4yB = 4y. Check the middle term: 2AB=2x4y=8xy2AB = 2 \cdot x \cdot 4y = 8xy, which matches the 8xy-8xy in the expression.

  3. Rewrite the expression as a single square.

    C=x28xy+16y2=(x4y)2C = x^2 - 8xy + 16y^2 = (x - 4y)^2

  4. Substitute the given value of the whole bracket. Since x4y=5x - 4y = 5:

    C=52=25C = 5^2 = 25

    The substitution is of the entire expression x4yx - 4y, not of individual values of xx and yy — that is what makes the problem solvable.

  5. Confirm with a concrete pair. Any (x,y)(x, y) with x4y=5x - 4y = 5 should give the same answer. Take y=0y = 0, x=5x = 5: 250+0=25 25 - 0 + 0 = 25 \ \checkmark. Take y=1y = 1, x=9x = 9: 8172+16=25 81 - 72 + 16 = 25 \ \checkmark. Take y=2y = -2, x=3x = -3: 948+64=25 9 - 48 + 64 = 25 \ \checkmark.

Answer

C=25C = 25

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