Cheat Sheet

삼각법 Formulas

대수학 II, 미적분 예비, 미적분, 공학에 등장하는 모든 삼각 항등식을 일곱 그룹으로 정리했습니다. 각 항등식에는 한 줄짜리 사용 메모가 함께 제공됩니다. 이 페이지를 북마크하고 숙제에서 낯선 항등식을 만나면 AI-Math 풀이기와 함께 사용하세요.

역수 항등식

csc

cscθ=1sinθ\csc\theta = \frac{1}{\sin\theta}

코시컨트는 사인의 역수입니다.

sec

secθ=1cosθ\sec\theta = \frac{1}{\cos\theta}

시컨트는 코사인의 역수입니다.

cot

cotθ=1tanθ\cot\theta = \frac{1}{\tan\theta}

코탄젠트는 탄젠트의 역수입니다.

몫 항등식

sin/cos에서 tan

tanθ=sinθcosθ\tan\theta = \frac{\sin\theta}{\cos\theta}

막히면 항상 tan을 sin/cos로 바꾸세요.

cos/sin에서 cot

cotθ=cosθsinθ\cot\theta = \frac{\cos\theta}{\sin\theta}

코탄젠트를 기본 두 함수로 표현.

Pythagorean identities

Main identity

sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1

The most-used identity in trigonometry — derives from the unit circle.

Tan form

1+tan2θ=sec2θ1 + \tan^2\theta = \sec^2\theta

Divide the main identity by cos2θ\cos^2\theta.

Cot form

1+cot2θ=csc2θ1 + \cot^2\theta = \csc^2\theta

Divide the main identity by sin2θ\sin^2\theta.

Even-odd / cofunction

sin is odd

sin(θ)=sinθ\sin(-\theta) = -\sin\theta

Sin reflects across the origin.

cos is even

cos(θ)=cosθ\cos(-\theta) = \cos\theta

Cos reflects across the y-axis.

tan is odd

tan(θ)=tanθ\tan(-\theta) = -\tan\theta

Inherits oddness from sin/cos.

Cofunction (sin)

sin(π2θ)=cosθ\sin\bigl(\tfrac{\pi}{2} - \theta\bigr) = \cos\theta

Sine of complementary angle = cosine of original.

Cofunction (tan)

tan(π2θ)=cotθ\tan\bigl(\tfrac{\pi}{2} - \theta\bigr) = \cot\theta

Tan-cot pair.

Sum and difference

sin sum

sin(A±B)=sinAcosB±cosAsinB\sin(A \pm B) = \sin A\cos B \pm \cos A\sin B

The single most useful sum formula.

cos sum

cos(A±B)=cosAcosBsinAsinB\cos(A \pm B) = \cos A\cos B \mp \sin A\sin B

Note the flipped sign in the result.

tan sum

tan(A±B)=tanA±tanB1tanAtanB\tan(A \pm B) = \frac{\tan A \pm \tan B}{1 \mp \tan A \tan B}

Useful when working purely in tangents.

Double-angle

sin 2θ

sin(2θ)=2sinθcosθ\sin(2\theta) = 2\sin\theta\cos\theta

Comes from sum identity with A=B=θA = B = \theta.

cos 2θ (three forms)

cos(2θ)=cos2θsin2θ=2cos2θ1=12sin2θ\cos(2\theta) = \cos^2\theta - \sin^2\theta = 2\cos^2\theta - 1 = 1 - 2\sin^2\theta

Pick the form that matches what you have.

tan 2θ

tan(2θ)=2tanθ1tan2θ\tan(2\theta) = \frac{2\tan\theta}{1 - \tan^2\theta}

Avoid when tanθ=±1\tan\theta = \pm 1 (undefined).

Half-angle

sin half-angle

sin(θ2)=±1cosθ2\sin\bigl(\tfrac{\theta}{2}\bigr) = \pm\sqrt{\tfrac{1 - \cos\theta}{2}}

Sign depends on quadrant of θ/2\theta/2.

cos half-angle

cos(θ2)=±1+cosθ2\cos\bigl(\tfrac{\theta}{2}\bigr) = \pm\sqrt{\tfrac{1 + \cos\theta}{2}}

Same caveat about sign.

tan half-angle

tan(θ2)=1cosθsinθ=sinθ1+cosθ\tan\bigl(\tfrac{\theta}{2}\bigr) = \frac{1 - \cos\theta}{\sin\theta} = \frac{\sin\theta}{1 + \cos\theta}

Two equivalent forms — pick whichever avoids division by zero.

Product-to-sum (advanced)

sin·cos

sinAcosB=12[sin(A+B)+sin(AB)]\sin A \cos B = \tfrac{1}{2}[\sin(A+B) + \sin(A-B)]

Converts product to sum — useful in integrals.

cos·cos

cosAcosB=12[cos(AB)+cos(A+B)]\cos A \cos B = \tfrac{1}{2}[\cos(A-B) + \cos(A+B)]

Same role for cosines.

sin·sin

sinAsinB=12[cos(AB)cos(A+B)]\sin A \sin B = \tfrac{1}{2}[\cos(A-B) - \cos(A+B)]

Note the negative sign.