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Cheat Sheet

삼각법 Formulas

대수학 II, 미적분 예비, 미적분, 공학에 등장하는 모든 삼각 항등식을 일곱 그룹으로 정리했습니다. 각 항등식에는 한 줄짜리 사용 메모가 함께 제공됩니다. 이 페이지를 북마크하고 숙제에서 낯선 항등식을 만나면 AI-Math 풀이기와 함께 사용하세요.

역수 항등식

csc

csc⁡θ=1sin⁡θ\csc\theta = \frac{1}{\sin\theta}

코시컨트는 사인의 역수입니다.

sec

sec⁡θ=1cos⁡θ\sec\theta = \frac{1}{\cos\theta}

시컨트는 코사인의 역수입니다.

cot

cot⁡θ=1tan⁡θ\cot\theta = \frac{1}{\tan\theta}

코탄젠트는 탄젠트의 역수입니다.

몫 항등식

sin/cos에서 tan

tan⁡θ=sin⁡θcos⁡θ\tan\theta = \frac{\sin\theta}{\cos\theta}

막히면 항상 tan을 sin/cos로 바꾸세요.

cos/sin에서 cot

cot⁡θ=cos⁡θsin⁡θ\cot\theta = \frac{\cos\theta}{\sin\theta}

코탄젠트를 기본 두 함수로 표현.

Pythagorean identities

Main identity

sin⁡2θ+cos⁡2θ=1\sin^2\theta + \cos^2\theta = 1

The most-used identity in trigonometry — derives from the unit circle.

Tan form

1+tan⁡2θ=sec⁡2θ1 + \tan^2\theta = \sec^2\theta

Divide the main identity by cos⁡2θ\cos^2\theta.

Cot form

1+cot⁡2θ=csc⁡2θ1 + \cot^2\theta = \csc^2\theta

Divide the main identity by sin⁡2θ\sin^2\theta.

Even-odd / cofunction

sin is odd

sin⁡(−θ)=−sin⁡θ\sin(-\theta) = -\sin\theta

Sin reflects across the origin.

cos is even

cos⁡(−θ)=cos⁡θ\cos(-\theta) = \cos\theta

Cos reflects across the y-axis.

tan is odd

tan⁡(−θ)=−tan⁡θ\tan(-\theta) = -\tan\theta

Inherits oddness from sin/cos.

Cofunction (sin)

sin⁡(π2−θ)=cos⁡θ\sin\bigl(\tfrac{\pi}{2} - \theta\bigr) = \cos\theta

Sine of complementary angle = cosine of original.

Cofunction (tan)

tan⁡(π2−θ)=cot⁡θ\tan\bigl(\tfrac{\pi}{2} - \theta\bigr) = \cot\theta

Tan-cot pair.

Sum and difference

sin sum

sin⁡(A±B)=sin⁡Acos⁡B±cos⁡Asin⁡B\sin(A \pm B) = \sin A\cos B \pm \cos A\sin B

The single most useful sum formula.

cos sum

cos⁡(A±B)=cos⁡Acos⁡B∓sin⁡Asin⁡B\cos(A \pm B) = \cos A\cos B \mp \sin A\sin B

Note the flipped sign in the result.

tan sum

tan⁡(A±B)=tan⁡A±tan⁡B1∓tan⁡Atan⁡B\tan(A \pm B) = \frac{\tan A \pm \tan B}{1 \mp \tan A \tan B}

Useful when working purely in tangents.

Double-angle

sin 2θ

sin⁡(2θ)=2sin⁡θcos⁡θ\sin(2\theta) = 2\sin\theta\cos\theta

Comes from sum identity with A=B=θA = B = \theta.

cos 2θ (three forms)

cos⁡(2θ)=cos⁡2θ−sin⁡2θ=2cos⁡2θ−1=1−2sin⁡2θ\cos(2\theta) = \cos^2\theta - \sin^2\theta = 2\cos^2\theta - 1 = 1 - 2\sin^2\theta

Pick the form that matches what you have.

tan 2θ

tan⁡(2θ)=2tan⁡θ1−tan⁡2θ\tan(2\theta) = \frac{2\tan\theta}{1 - \tan^2\theta}

Avoid when tan⁡θ=±1\tan\theta = \pm 1 (undefined).

Half-angle

sin half-angle

sin⁡(θ2)=±1−cos⁡θ2\sin\bigl(\tfrac{\theta}{2}\bigr) = \pm\sqrt{\tfrac{1 - \cos\theta}{2}}

Sign depends on quadrant of θ/2\theta/2.

cos half-angle

cos⁡(θ2)=±1+cos⁡θ2\cos\bigl(\tfrac{\theta}{2}\bigr) = \pm\sqrt{\tfrac{1 + \cos\theta}{2}}

Same caveat about sign.

tan half-angle

tan⁡(θ2)=1−cos⁡θsin⁡θ=sin⁡θ1+cos⁡θ\tan\bigl(\tfrac{\theta}{2}\bigr) = \frac{1 - \cos\theta}{\sin\theta} = \frac{\sin\theta}{1 + \cos\theta}

Two equivalent forms — pick whichever avoids division by zero.

Product-to-sum (advanced)

sin·cos

sin⁡Acos⁡B=12[sin⁡(A+B)+sin⁡(A−B)]\sin A \cos B = \tfrac{1}{2}[\sin(A+B) + \sin(A-B)]

Converts product to sum — useful in integrals.

cos·cos

cos⁡Acos⁡B=12[cos⁡(A−B)+cos⁡(A+B)]\cos A \cos B = \tfrac{1}{2}[\cos(A-B) + \cos(A+B)]

Same role for cosines.

sin·sin

sin⁡Asin⁡B=12[cos⁡(A−B)−cos⁡(A+B)]\sin A \sin B = \tfrac{1}{2}[\cos(A-B) - \cos(A+B)]

Note the negative sign.