Solve segitiga siku-siku dengan sisi tegak 20 dan 21 — c = 29

Problem

$a^2 + b^2 = c^2,\ a=20,\ b=21$

Step-by-step solution

Terapkan $a^2 + b^2 = c^2$ dengan $a = 20$ , $b = 21$ .
$400 + 441 = 841$ .
$c = \sqrt{841} = 29$ .
$(20, 21, 29)$ adalah tripel Pythagoras primitif.

Answer

$c = 29$

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