Wavelength to Frequency Calculator

Convert between wavelength, frequency, photon energy and wavenumber with step-by-step solutions
Convert a wavelength of 500 nm to frequency
Find the wavelength of a 98.5 MHz FM radio wave
Find the photon energy of 500 nm light in joules and eV
A sound wave of 440 Hz travels at 343 m/s. Find its wavelength.

The Wave Equation c = fλ

Every travelling wave obeys one relation between its speed, frequency and wavelength:

v=fλf=vλ,λ=vfv = f\lambda \quad\Longrightarrow\quad f = \frac{v}{\lambda}, \quad \lambda = \frac{v}{f}

Symbols and SI units:

  • vv — wave speed, metres per second (m/s). For light in vacuum v=c=2.998×108v = c = 2.998 \times 10^8 m/s; for sound in air at 20 °C, v343v \approx 343 m/s.
  • ff — frequency, hertz (Hz), meaning cycles per second
  • λ\lambda — wavelength, metres (m)

When it applies: to any periodic wave in a uniform medium.

The assumption people forget: cc is the speed of light in vacuum. Inside a medium of refractive index nn the speed is v=c/nv = c/n, so the wavelength shortens to λ/n\lambda/n while the frequency stays the same. Frequency is fixed by the source; wavelength is not.

Two further ways to state the same timing are the period T=1/fT = 1/f, in seconds, and the angular frequency ω=2πf\omega = 2\pi f, in radians per second. A 5050 Hz mains wave has a period of 2020 ms.

Photon Energy and Wavenumber

For electromagnetic radiation, frequency also sets the energy of a single photon:

E=hf=hcλE = hf = \frac{hc}{\lambda}

  • EE — photon energy, joules (J); divide by 1.602×10191.602 \times 10^{-19} to convert to electronvolts (eV)
  • hh — Planck's constant, 6.626×10346.626 \times 10^{-34} J·s

Spectroscopists often quote the wavenumber instead, the number of cycles per centimetre:

ν~=1λ[cm1]\tilde{\nu} = \frac{1}{\lambda} \quad [\text{cm}^{-1}]

with λ\lambda expressed in centimetres.

Unit trap: wavelengths are usually quoted in nanometres (1 nm=1091\ \text{nm} = 10^{-9} m) and frequencies in MHz or GHz (1 MHz=1061\ \text{MHz} = 10^6 Hz). Convert everything to metres and hertz before dividing, or the exponent will be wrong by several orders of magnitude.

The assumption people forget: E=hfE = hf is the energy of one photon, not of a beam.

Common Mistakes to Avoid

  • Using cc for sound — sound in air travels at about 343343 m/s, roughly a million times slower than light. Using 3×1083 \times 10^8 m/s for a sound problem is off by six orders of magnitude.
  • Forgetting the nano prefix500500 nm is 5.00×1075.00 \times 10^{-7} m, not 500500 m.
  • Assuming wavelength is unchanged in glass or water — the frequency is what stays constant when light enters a medium; the wavelength divides by nn.
  • Mixing metres and centimetres in the wavenumberν~\tilde{\nu} in cm⁻¹ needs λ\lambda in cm.
  • Rounding cc too early — using 3×1083 \times 10^8 m/s instead of 2.998×1082.998 \times 10^8 m/s introduces a 0.07%0.07\% error, which matters in spectroscopy.
  • Confusing period with frequency — they are reciprocals, so a period of 0.020.02 s corresponds to a frequency of 5050 Hz.
  • Using the wrong speed for a wave on a string — that speed is set by tension and linear density, v=T/μv = \sqrt{T/\mu}, and has nothing to do with the speed of light.

Examples

Step 1: Convert to metres: λ=500 nm=5.00×107 m\lambda = 500\ \text{nm} = 5.00 \times 10^{-7}\ \text{m}
Step 2: Use f=c/λf = c/\lambda with c=2.998×108 m/sc = 2.998 \times 10^8\ \text{m/s}
Step 3: f=(2.998×108 m/s)÷(5.00×107 m)f = (2.998 \times 10^8\ \text{m/s}) \div (5.00 \times 10^{-7}\ \text{m})
Step 4: f=5.996×1014 s1=5.996×1014 Hzf = 5.996 \times 10^{14}\ \text{s}^{-1} = 5.996 \times 10^{14}\ \text{Hz}
Answer: f5.996×1014f \approx 5.996 \times 10^{14} Hz (about 600600 THz)

Step 1: Convert to hertz: f=98.5 MHz=9.85×107 Hzf = 98.5\ \text{MHz} = 9.85 \times 10^7\ \text{Hz}
Step 2: Use λ=c/f\lambda = c/f, taking the speed in air as essentially cc
Step 3: λ=(2.998×108 m/s)÷(9.85×107 Hz)\lambda = (2.998 \times 10^8\ \text{m/s}) \div (9.85 \times 10^7\ \text{Hz})
Step 4: λ=3.04 m\lambda = 3.04\ \text{m}
Answer: λ3.04\lambda \approx 3.04 m

Step 1: From the first example, f=5.996×1014 Hzf = 5.996 \times 10^{14}\ \text{Hz}
Step 2: E=hf=(6.626×1034 J\cdotps)(5.996×1014 s1)E = hf = (6.626 \times 10^{-34}\ \text{J·s})(5.996 \times 10^{14}\ \text{s}^{-1})
Step 3: E=3.973×1019 JE = 3.973 \times 10^{-19}\ \text{J}
Step 4: Convert: E=(3.973×1019 J)÷(1.602×1019 J/eV)=2.48 eVE = (3.973 \times 10^{-19}\ \text{J}) \div (1.602 \times 10^{-19}\ \text{J/eV}) = 2.48\ \text{eV}
Answer: E3.97×1019E \approx 3.97 \times 10^{-19} J =2.48= 2.48 eV

Frequently Asked Questions

Divide the wave speed by the wavelength: f = v / λ. For light in vacuum use v = c = 2.998 × 10⁸ m/s, and convert the wavelength to metres first — 500 nm is 5.00 × 10⁻⁷ m. The result comes out in hertz.

The frequency stays the same because it is set by the source, but the speed drops to v = c/n, so the wavelength shortens to λ/n. In water (n ≈ 1.33) a 500 nm beam has a wavelength of about 376 nm while still being the same colour.

Yes, but you must use the speed of sound in the relevant medium, not the speed of light. In air at 20 °C that is about 343 m/s, so a 440 Hz note has a wavelength of 343 ÷ 440 = 0.78 m.

Wavenumber is the reciprocal of wavelength, ṽ = 1/λ, and is normally quoted in cm⁻¹, so express λ in centimetres first. A 500 nm wavelength is 5 × 10⁻⁵ cm, giving a wavenumber of 20,000 cm⁻¹.

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