Square Root Calculator and Chart

Evaluate or simplify any square root, with the perfect squares from 1 to 100
sqrt(72)
sqrt(50/9)
sqrt(48) + sqrt(27)
sqrt(196)

Perfect Squares 1 to 100

n\sqrt{n} asks: what non-negative number, multiplied by itself, gives nn? When nn is a perfect square the answer is a whole number, and knowing these ten by heart is what makes every other square root question fast:

nnn2n^2nnn2n^2
11636
24749
39864
416981
52510100

Beyond 100 the pattern continues: 112=12111^2 = 121, 122=14412^2 = 144, 132=16913^2 = 169, 142=19614^2 = 196, 152=22515^2 = 225.

Everything else is irrational тАФ 2=1.41421тАж\sqrt{2} = 1.41421\ldots never terminates or repeats. The chart is still the tool you use, because the exact form of 72\sqrt{72} is found by hunting for the largest perfect square hiding inside 72.

Reading the chart backwards. To place 60\sqrt{60}, find the two perfect squares it sits between: 49<60<6449 < 60 < 64, so the answer lies between 7 and 8, and closer to 8. That bracketing trick is enough to sanity-check any calculator result before you trust it.

The Rules, and How to Simplify a Root

Two rules do almost all the work:

ab=aтАЙbab=ab\sqrt{ab} = \sqrt{a}\,\sqrt{b} \qquad \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}

To simplify n\sqrt{n}:

  1. Find the largest perfect square that divides nn. For 72 that is 36, since 72=36├Ч272 = 36 \times 2.
  2. Split the root: 72=362\sqrt{72} = \sqrt{36}\sqrt{2}.
  3. Take the square root of the perfect square and leave the rest inside: 626\sqrt{2}.

If you cannot spot the largest square, prime factorise instead and pull out each pair: 72=23├Ч3272 = 2^3 \times 3^2, so one pair of 2s and one pair of 3s come out as 2├Ч3=62 \times 3 = 6, leaving a single 2 behind.

Like radicals add. 43+33=734\sqrt{3} + 3\sqrt{3} = 7\sqrt{3}, exactly as 4x+3x=7x4x + 3x = 7x. Unlike radicals, such as 2+3\sqrt{2} + \sqrt{3}, cannot be combined at all.

Common Mistakes to Avoid

  • The root does not distribute over addition. 9+16=25=5\sqrt{9 + 16} = \sqrt{25} = 5, but 9+16=3+4=7\sqrt{9} + \sqrt{16} = 3 + 4 = 7. It splits over multiplication and division only.
  • 25\sqrt{25} is 5, not ┬▒5\pm 5. The radical symbol means the principal (non-negative) root. The ┬▒\pm appears when you solve x2=25x^2 = 25 yourself, because that equation has two roots.
  • Stopping at a square you can still pull out. 72=218\sqrt{72} = 2\sqrt{18} is true but not simplified тАФ 18 still contains a factor of 9.
  • Adding unlike radicals. 2+3тЙа5\sqrt{2} + \sqrt{3} \neq \sqrt{5}; check numerically: 1.414+1.732=3.1461.414 + 1.732 = 3.146, while 5тЙИ2.236\sqrt{5} \approx 2.236.
  • Squaring away a root without checking. Squaring both sides of x=тИТ3\sqrt{x} = -3 gives x=9x = 9, but 9=3тЙатИТ3\sqrt{9} = 3 \neq -3, so it is extraneous.

Examples

Step 1: Look for the largest perfect square dividing 72: 72=36├Ч272 = 36 \times 2.
Step 2: Split the radical: 72=36тЛЕ2\sqrt{72} = \sqrt{36} \cdot \sqrt{2}.
Step 3: 36=6\sqrt{36} = 6, and 2 has no square factors, so it stays inside.
Step 4: Check: (62)2=36├Ч2=72(6\sqrt{2})^2 = 36 \times 2 = 72 тЬУ
Answer: 62тЙИ8.4856\sqrt{2} \approx 8.485

Step 1: Split the quotient: 509=509\sqrt{\frac{50}{9}} = \frac{\sqrt{50}}{\sqrt{9}}.
Step 2: The denominator is a perfect square: 9=3\sqrt{9} = 3.
Step 3: Simplify the numerator: 50=25├Ч250 = 25 \times 2, so 50=52\sqrt{50} = 5\sqrt{2}.
Step 4: Combine: 523\frac{5\sqrt{2}}{3}.
Answer: 523тЙИ2.357\dfrac{5\sqrt{2}}{3} \approx 2.357

Step 1: 48=16├Ч348 = 16 \times 3, so 48=43\sqrt{48} = 4\sqrt{3}.
Step 2: 27=9├Ч327 = 9 \times 3, so 27=33\sqrt{27} = 3\sqrt{3}.
Step 3: Both terms now carry the same radical 3\sqrt{3}, so they are like terms.
Step 4: Add the coefficients: 43+33=734\sqrt{3} + 3\sqrt{3} = 7\sqrt{3}.
Step 5: Check: 6.928+5.196=12.1246.928 + 5.196 = 12.124, and 73тЙИ12.1247\sqrt{3} \approx 12.124 тЬУ
Answer: 73тЙИ12.1247\sqrt{3} \approx 12.124

Frequently Asked Questions

Divide the number by the largest perfect square that goes into it, then take the root of that square outside the radical. If no square is obvious, prime factorise and bring out one copy of every pair of identical primes, leaving the unpaired ones inside.

The radical symbol itself gives only the non-negative root, so the square root of 25 is 5. Two answers appear when you solve an equation such as x squared equals 25, because both 5 and -5 square to 25 тАФ the plus-or-minus comes from the equation, not from the symbol.

Isolate the radical on one side and square both sides, which cancels it. Squaring can introduce solutions that do not satisfy the original equation, so substitute every answer back in and discard any that fail.

For any non-negative x, the square root of x times the square root of x equals x, because that is the definition of the root. This is what lets you rationalise a denominator: multiplying 6 over root 2 by root 2 over root 2 turns the bottom into a plain 2.

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