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geometry · worked example

Solve 10 त्रिज्या वाला वृत्त — A = 100π ≈ 314.16

Method: वृत्त के क्षेत्रफल का सूत्र. Verified step-by-step solution with our free AI math solver.
Problem

A=πr2, r=10A = \pi r^2,\ r = 10

Step-by-step solution

  1. A=πr2A = \pi r^2 को r=10r = 10 के साथ लागू करें।

  2. A=π⋅100=100π≈314.16A = \pi \cdot 100 = 100\pi \approx 314.16।

Answer

A=100π≈314.16A = 100\pi \approx 314.16

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