Rhombus Shape Solver

Find the area, side, diagonals, and angles of a rhombus with step-by-step working
Area of a rhombus with diagonals 10 and 24
Area of a rhombus with side 8 and angle 60 degrees
Find the other diagonal of a rhombus with area 96 and one diagonal 16
Find the side and perimeter of a rhombus with diagonals 6 and 8

What Is a Rhombus?

A rhombus is a quadrilateral with all four sides equal in length. That single condition forces every other property:

  • Opposite sides are parallel, so every rhombus is a parallelogram (a "diamond" tilted parallelogram, not necessarily upright).
  • Opposite angles are equal; consecutive angles are supplementary, summing to 180180^\circ.
  • The diagonals are perpendicular bisectors of each other, meeting at 9090^\circ and cutting each other exactly in half.
  • Each diagonal bisects the two angles it passes through.
  • It has 2 lines of symmetry — the diagonals — and rotational symmetry of order 2.

Because the perpendicular diagonals split the rhombus into four congruent right triangles with legs d1/2d_1/2 and d2/2d_2/2, the side satisfies

s=(d12)2+(d22)2s = \sqrt{\left(\frac{d_1}{2}\right)^2 + \left(\frac{d_2}{2}\right)^2}

and the perimeter is simply P=4sP = 4s.

Rhombus Area Formulas

Three formulas, each matched to what you are given.

From the diagonals — the one to reach for first:

A=d1d22A = \frac{d_1 \cdot d_2}{2}

From base and height, since a rhombus is a parallelogram:

A=bhA = b \cdot h

Here hh is the perpendicular distance between two parallel sides, not a slanted side.

From a side and an included angle:

A=s2sinθA = s^2 \sin\theta

This works for either angle, because sinθ=sin(180θ)\sin\theta = \sin(180^\circ - \theta) and the two angles of a rhombus are supplementary.

Choosing and rearranging

GivenUse
Both diagonalsA=d1d2/2A = d_1 d_2 / 2
Side + angleA=s2sinθA = s^2 \sin\theta
Side + heightA=shA = s h
Area + one diagonald2=2A/d1d_2 = 2A/d_1

All three assume the figure really is a rhombus — four equal sides. If only opposite sides match, use the parallelogram formulas instead.

Rhombus, Square, Rectangle, and Parallelogram

The classification questions all follow from one hierarchy: square \subset rhombus \subset parallelogram \subset quadrilateral.

  • Is a square a rhombus? Yes, always. A square has four equal sides, which is the definition of a rhombus.
  • Is a rhombus a square? Only when its angles are 9090^\circ (equivalently, when its diagonals are equal). A tilted rhombus is not a square.
  • Is a rectangle a rhombus? Only if the rectangle is a square. A 3×53 \times 5 rectangle has unequal adjacent sides, so it fails the definition.
  • Is a rhombus a parallelogram? Yes — equal opposite sides force both pairs to be parallel.
  • Is a rhombus a polygon? Yes: a closed four-sided plane figure, so a quadrilateral.

Common mistakes

  • Using A=s2A = s^2. That is the square's formula; a rhombus with the same side has a smaller area unless θ=90\theta = 90^\circ.
  • Multiplying the diagonals and forgetting the 12\tfrac{1}{2}.
  • Treating a slanted side as the height in A=bhA = bh.
  • Claiming the diagonals are equal — they are perpendicular, not congruent, unless the rhombus is a square.

示例题目

Step 1: Area: A=d1d22=10×242=2402=120A = \dfrac{d_1 d_2}{2} = \dfrac{10 \times 24}{2} = \dfrac{240}{2} = 120
Step 2: Half-diagonals: 10/2=510/2 = 5 and 24/2=1224/2 = 12
Step 3: Side (right triangle): s=52+122=25+144=169=13s = \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13
Step 4: Perimeter: P=4×13=52P = 4 \times 13 = 52
Answer: A=120A = 120, s=13s = 13, P=52P = 52

Step 1: A=s2sinθ=82sin60A = s^2 \sin\theta = 8^2 \sin 60^\circ
Step 2: 82=648^2 = 64 and sin60=320.86603\sin 60^\circ = \dfrac{\sqrt{3}}{2} \approx 0.86603
Step 3: A=64×32=323A = 64 \times \dfrac{\sqrt{3}}{2} = 32\sqrt{3}
Step 4: 32332×1.73205=55.4332\sqrt{3} \approx 32 \times 1.73205 = 55.43
Answer: A=32355.43A = 32\sqrt{3} \approx 55.43

Step 1: Rearrange A=d1d2/2A = d_1 d_2/2: d2=2Ad1=2×9616=19216=12d_2 = \dfrac{2A}{d_1} = \dfrac{2 \times 96}{16} = \dfrac{192}{16} = 12
Step 2: Half-diagonals: 16/2=816/2 = 8 and 12/2=612/2 = 6
Step 3: Side: s=82+62=64+36=100=10s = \sqrt{8^2 + 6^2} = \sqrt{64 + 36} = \sqrt{100} = 10
Step 4: Perimeter: P=4×10=40P = 4 \times 10 = 40
Answer: d2=12d_2 = 12, s=10s = 10, P=40P = 40

常见问题

Yes. A rhombus is defined as a quadrilateral with four equal sides, and a square satisfies that. A square is simply the special rhombus whose angles are all 90°, so every square is a rhombus but most rhombuses are not squares.

Only when the rectangle happens to be a square. A rectangle guarantees four right angles but not four equal sides, so a 4 × 7 rectangle is not a rhombus. The two shapes overlap in exactly one figure: the square.

Like a square pushed sideways — a diamond with four equal sides and two pairs of parallel sides, where opposite angles match but the corners are generally not right angles. Its diagonals cross at 90° inside the shape, one usually longer than the other.

Two: the two diagonals. Folding along either diagonal maps the rhombus onto itself. A square, being a special rhombus, has four because its horizontal and vertical midlines are also lines of symmetry.

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