ProblemV=πr2h, r=3, h=10V = \pi r^2 h,\ r=3,\ h=10V=πr2h, r=3, h=10分步解答圆柱的体积:V=πr2hV = \pi r^2 hV=πr2h。代入 r=3r = 3r=3、h=10h = 10h=10:V=π⋅9⋅10=90πV = \pi \cdot 9 \cdot 10 = 90\piV=π⋅9⋅10=90π。取近似值:≈282.74\approx 282.74≈282.74。答案V=90π≈282.74V = 90\pi \approx 282.74V=90π≈282.74想解其他题?打开 volume 求解器 →相关例题/solve/geometry/volume-cube-side-4/solve/geometry/volume-sphere-radius-5