Problemx2−5x+4=0x^2 - 5x + 4 = 0x2−5x+4=0分步解答找出两个相乘得 444、相加得 −5-5−5 的数。两者都是负数(乘积为正、和为负):(−1,−4)(-1, -4)(−1,−4)。因式分解:(x−1)(x−4)=0(x - 1)(x - 4) = 0(x−1)(x−4)=0。求解:x=1x = 1x=1 或 x=4x = 4x=4。答案x=1orx=4x = 1 \quad \text{or} \quad x = 4x=1orx=4想解其他题?打开 quadratic 求解器 →相关例题/solve/algebra/x2-minus-7x-plus-12