Problemx2+4x+4=0x^2 + 4x + 4 = 0x2+4x+4=0分步解答辨认为 (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2(a+b)2=a2+2ab+b2,其中 a=xa = xa=x、b=2b = 2b=2。分解:(x+2)2=0(x + 2)^2 = 0(x+2)2=0。求解:x=−2x = -2x=−2 —— 重根。答案x=−2(double root)x = -2 \quad \text{(double root)}x=−2(double root)想解其他题?打开 quadratic 求解器 →相关例题/solve/algebra/x2-plus-2x-plus-1