Problem2x2+7x+3=02x^2 + 7x + 3 = 02x2+7x+3=0分步解答确定 a=2a = 2a=2、b=7b = 7b=7、c=3c = 3c=3。计算 ac=2⋅3=6ac = 2 \cdot 3 = 6ac=2⋅3=6。找出两个相乘为 666、相加为 b=7b = 7b=7 的数:就是 111 和 666。拆开中间项:2x2+x+6x+32x^2 + x + 6x + 32x2+x+6x+3。通过分组因式分解:x(2x+1)+3(2x+1)=(2x+1)(x+3)x(2x + 1) + 3(2x + 1) = (2x + 1)(x + 3)x(2x+1)+3(2x+1)=(2x+1)(x+3)。令每个因式为零:x=−12x = -\tfrac{1}{2}x=−21 或 x=−3x = -3x=−3。答案x=−12orx=−3x = -\tfrac{1}{2} \quad \text{or} \quad x = -3x=−21orx=−3想解其他题?打开 quadratic 求解器 →相关例题/solve/algebra/2x2-minus-3x-minus-2延伸阅读/blog/mastering-quadratic-equations-complete-guide/blog/factoring-polynomials-step-by-step