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Arithmetic · real student question

Use the order of operations to simplify 7^2 - 72 / 6^2 * 9 - 6.

Question

Use the order of operations to simplify the expression.

72−72÷62⋅9−67^{2}-72\div 6^{2}\cdot 9-6

Step-by-step solution

  1. Evaluate the exponents first. There are no brackets, so powers come next in the hierarchy:

    72=49,62=36,7^{2}=49,\qquad 6^{2}=36,

    giving 49−72÷36⋅9−649-72\div 36\cdot 9-6.

  2. Recognise that division and multiplication share a rank. Neither outranks the other; they are performed in the order they appear, reading left to right. Here the division comes first:

    72÷36=2.72\div 36=2.

    Multiplying 36⋅9=32436\cdot 9=324 first would give 72÷324=2972\div 324=\tfrac29 and a completely different answer — that is the trap this problem is built around.

  3. Continue left to right with the multiplication.

    2⋅9=18,2\cdot 9=18,

    so the expression is now 49−18−649-18-6.

  4. Perform the additions and subtractions, again left to right.

    49−18=31,31−6=25.49-18=31,\qquad 31-6=25.

  5. Check by rewriting as a single fraction. The middle term is 72⋅936=64836=18\dfrac{72\cdot 9}{36}=\dfrac{648}{36}=18, confirming the same value, so

    72−72÷62⋅9−6=25.7^{2}-72\div 6^{2}\cdot 9-6=25.

Answer

2525

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