Arithmetic · real student question

Simplify the fraction whose numerator is 7(4 - 3)/5 minus (2(2 - 8) - 3(8 + 1))/15, all divided by 3.

Question

Simplify

7(43)52(28)3(8+1)153\frac{\dfrac{7(4-3)}{5}-\dfrac{2(2-8)-3(8+1)}{15}}{3}

Step-by-step solution

  1. Work from the innermost brackets outward. A nested fraction is evaluated like any expression: finish the numerator completely, finish the denominator, then divide.

    43=1,28=6,8+1=9.4-3=1,\qquad 2-8=-6,\qquad 8+1=9.

  2. Simplify the first term of the numerator.

    7(1)5=75.\frac{7(1)}{5}=\frac{7}{5}.

  3. Simplify the second term's numerator. Multiply before subtracting, and mind that both products are negative contributions:

    2(6)3(9)=1227=39,2(-6)-3(9)=-12-27=-39,

    so the second fraction is 3915=135\dfrac{-39}{15}=-\dfrac{13}{5}.

  4. Subtract the two fractions. Subtracting a negative adds:

    75(135)=7+135=205=4.\frac{7}{5}-\left(-\frac{13}{5}\right)=\frac{7+13}{5}=\frac{20}{5}=4.

    The common denominator 55 makes this immediate — a strong hint that the numerator was designed to come out whole.

  5. Divide by the outer 3.

    43.\frac{4}{3}.

    As a decimal this is 1.331.3\overline{3}; as a mixed number, 1131\tfrac13.

Answer

43\frac{4}{3}

Need to solve a different problem like this? Open the solver →