Solve for :
Expand the bracket and watch the double negative.
The inside the bracket meets the outside and produces .
Collect the terms. , so the equation is
A useful check on this coefficient: must be , and the constant that appeared is exactly — the same number, which is a signature of the shift.
Subtract the constant.
The right-hand side lands on a clean two-decimal value, which is a hint the source problem was designed around it.
Divide and reduce to lowest terms. Scale by and cancel the factor :
is prime and , so no further cancellation is possible.
Get the decimal and verify. Then and , matching the original right-hand side exactly.
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