Solve for :
Move the known reciprocal across.
Since the result is positive, so a positive is expected.
Use the difference-of-reciprocals identity.
One subtraction and one multiplication replace two long divisions, which keeps the rounding error out of the calculation.
Evaluate both parts.
(Check: plus gives .)
Take the reciprocal.
Notice how sensitive this is: the numerator differs from the previous problem's by only , yet the answer moves by about .
Check the arithmetic backwards. and , summing to ; and ✓. So .
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