Resistivity of Metals Chart & Calculator

Resistivity values for common metals, plus resistance and temperature correction, step by step
Find the resistance of 50 m of copper with a 10 mm^2 cross-section
Compare copper and aluminium conductors of the same size over 50 m
Correct a 0.084 ohm copper conductor from 20 C to 75 C
Find the nichrome wire length for a 48 ohm heating element of 0.5 mm diameter

What Electrical Resistance Actually Is

Resistance is how strongly a particular object opposes the flow of charge, defined by

R=VI[╬й]R = \frac{V}{I} \qquad [\Omega]

with VV in volts and II in amperes. One ohm is one volt per ampere. It is a property of the object тАФ this length of this wire.

Resistivity ╧Б\rho is the corresponding property of the material, independent of shape, and the two are joined by the geometry:

R=╧БLA╧Б=RALR = \frac{\rho L}{A} \qquad \rho = \frac{RA}{L}

  • ╧Б\rho тАФ resistivity, ohm-metres (╬й┬╖m)
  • LL тАФ length, metres (m)
  • AA тАФ cross-sectional area, square metres (m┬▓)

Physically, resistance is the scattering of conduction electrons by lattice vibrations and by impurities. Heating the metal increases the vibrations, which is why metals get more resistive as they warm.

The operating assumption: a uniform, homogeneous conductor at a stated temperature carrying DC.

Resistivity of Metals Chart

Values at 20 ┬░C, with the temperature coefficient ╬▒\alpha per ┬░C referenced to 20 ┬░C:

Material╧Б\rho (╬й┬╖m)╬▒\alpha (per ┬░C)
Silver1.59├Ч10тИТ81.59 \times 10^{-8}0.00380.0038
Copper1.68├Ч10тИТ81.68 \times 10^{-8}0.003930.00393
Gold2.44├Ч10тИТ82.44 \times 10^{-8}0.00340.0034
Aluminium2.65├Ч10тИТ82.65 \times 10^{-8}0.004290.00429
Tungsten5.60├Ч10тИТ85.60 \times 10^{-8}0.00450.0045
Iron9.71├Ч10тИТ89.71 \times 10^{-8}0.00500.0050
Nichrome1.10├Ч10тИТ61.10 \times 10^{-6}0.00040.0004

Correct to another temperature with the linear relation

╧БT=╧Б20[1+╬▒(TтИТ20)]\rho_T = \rho_{20}\left[1 + \alpha (T - 20)\right]

Nichrome is roughly 6565 times more resistive than copper and barely changes with temperature, which is exactly what a heating element needs.

Treat these as nominal textbook values. Real conductors vary with alloy, temper and purity, and a design that depends on the number should use the supplier's certified data, with any current-carrying decision made under the applicable wiring code.

Common Mistakes to Avoid

  • Using a resistivity without its temperature тАФ the chart is at 20 ┬░C, and a conductor running hot is measurably more resistive.
  • Leaving the area in mm┬▓ тАФ 1010 mm┬▓ is 1├Ч10тИТ51 \times 10^{-5} m┬▓. Skipping this is a factor of a million.
  • Swapping resistance and resistivity тАФ resistivity is ╬й┬╖m and belongs to the material; resistance is ╬й and belongs to the object.
  • Assuming aluminium can simply replace copper тАФ for the same resistance an aluminium conductor needs roughly 58%58\% more cross-sectional area.
  • Applying the linear ╬▒\alpha far outside its range тАФ it is a first-order fit valid near the reference temperature, not down to cryogenic or up to melting temperatures.
  • Forgetting that heating is self-reinforcing тАФ current heats the conductor, which raises resistance, which raises the drop.
  • Reading nichrome's low ╬▒\alpha as low resistivity тАФ its resistivity is very high; it is the change with temperature that is small.

Examples

Step 1: Area: A=10┬аmm2=1.0├Ч10тИТ5┬аm2A = 10\ \text{mm}^2 = 1.0 \times 10^{-5}\ \text{m}^2
Step 2: Copper: R=(1.68├Ч10тИТ8┬а╬йтЛЕm)(50┬аm)├╖(1.0├Ч10тИТ5┬аm2)=(8.40├Ч10тИТ7)├╖(1.0├Ч10тИТ5)=0.0840┬а╬йR = (1.68 \times 10^{-8}\ \Omega\cdot\text{m})(50\ \text{m}) \div (1.0 \times 10^{-5}\ \text{m}^2) = (8.40 \times 10^{-7}) \div (1.0 \times 10^{-5}) = 0.0840\ \Omega
Step 3: Aluminium: R=(2.65├Ч10тИТ8)(50)├╖(1.0├Ч10тИТ5)=(1.325├Ч10тИТ6)├╖(1.0├Ч10тИТ5)=0.1325┬а╬йR = (2.65 \times 10^{-8})(50) \div (1.0 \times 10^{-5}) = (1.325 \times 10^{-6}) \div (1.0 \times 10^{-5}) = 0.1325\ \Omega
Step 4: Ratio: 0.1325├╖0.0840=1.580.1325 \div 0.0840 = 1.58, so aluminium is 58%58\% more resistive at the same size
Step 5: To match: AAl=10┬аmm2├Ч1.58=15.8┬аmm2A_{\text{Al}} = 10\ \text{mm}^2 \times 1.58 = 15.8\ \text{mm}^2
Answer: Copper 0.08400.0840 ╬й, aluminium 0.13250.1325 ╬й; about 15.815.8 mm┬▓ of aluminium matches 1010 mm┬▓ of copper

Step 1: Temperature rise above the reference: 75┬атИШCтИТ20┬атИШC=55┬атИШC75\ ^\circ\text{C} - 20\ ^\circ\text{C} = 55\ ^\circ\text{C}
Step 2: ╬▒╬ФT=(0.00393┬атИШCтИТ1)(55┬атИШC)=0.2162\alpha \Delta T = (0.00393\ ^\circ\text{C}^{-1})(55\ ^\circ\text{C}) = 0.2162
Step 3: R75=R20(1+0.2162)=(0.0840┬а╬й)(1.2162)R_{75} = R_{20}(1 + 0.2162) = (0.0840\ \Omega)(1.2162)
Step 4: R75=0.1022┬а╬йR_{75} = 0.1022\ \Omega
Step 5: That is a 21.6%21.6\% increase, which is why voltage-drop checks are done at the conductor's operating temperature
Answer: R75тЙИ0.102R_{75} \approx 0.102 ╬й, about 22%22\% above the 20 ┬░C value

Step 1: A=╧Аd2/4=╧А(0.50├Ч10тИТ3┬аm)2/4=╧А(2.50├Ч10тИТ7┬аm2)/4=1.963├Ч10тИТ7┬аm2A = \pi d^2/4 = \pi (0.50 \times 10^{-3}\ \text{m})^2/4 = \pi (2.50 \times 10^{-7}\ \text{m}^2)/4 = 1.963 \times 10^{-7}\ \text{m}^2
Step 2: Rearrange: L=RA/╧БL = RA/\rho
Step 3: L=(48┬а╬й)(1.963├Ч10тИТ7┬аm2)├╖(1.10├Ч10тИТ6┬а╬йтЛЕm)L = (48\ \Omega)(1.963 \times 10^{-7}\ \text{m}^2) \div (1.10 \times 10^{-6}\ \Omega\cdot\text{m})
Step 4: Numerator: 9.425├Ч10тИТ6┬а╬йтЛЕm29.425 \times 10^{-6}\ \Omega\cdot\text{m}^2, so L=8.57┬аmL = 8.57\ \text{m}
Step 5: On 240240 V: I=240┬аV├╖48┬а╬й=5.0┬аAI = 240\ \text{V} \div 48\ \Omega = 5.0\ \text{A}
Step 6: P=VI=(240┬аV)(5.0┬аA)=1200┬аWP = VI = (240\ \text{V})(5.0\ \text{A}) = 1200\ \text{W}
Answer: LтЙИ8.57L \approx 8.57 m of wire, drawing 5.05.0 A and dissipating 12001200 W on 240240 V

Frequently Asked Questions

Resistance is the ratio of the voltage across an object to the current through it, R = V/I, measured in ohms. Microscopically it is the scattering of conduction electrons by lattice vibrations and impurities, which is why metals become more resistive as they get hotter.

Resistivity is a material property in ohm-metres and does not depend on shape. Resistance is a property of a specific object in ohms and depends on length and cross-section as well as material, through R = rho L / A.

Silver, at about 1.59 x 10^-8 ohm-metres at 20 C, just below copper at 1.68 x 10^-8. Copper is used almost everywhere instead because it costs far less and does not tarnish into a poorly conducting surface layer.

For metals, use R_T = R_20 [1 + alpha (T - 20)] with alpha in reciprocal degrees Celsius. Copper's alpha of 0.00393 means a conductor at 75 C has about 22% more resistance than at 20 C. The relation is a first-order fit near the reference temperature.

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