Conductivity to Resistivity Calculator

Convert between sigma and rho and find resistance from resistivity, step by step
Convert a conductivity of 5.96e7 S/m to resistivity
Convert a resistivity of 2.65e-8 ohm-m to conductivity
Find the resistivity of a 30 m wire of 1.024 mm diameter measuring 0.61 ohm
Find the resistance of 50 m of copper with a 10 mm^2 cross-section

Conductivity and Resistivity Are Reciprocals

Electrical conductivity and resistivity describe the same material property from opposite ends:

sigma=frac1rhoqquadLongleftrightarrowqquadrho=frac1sigma\\sigma = \\frac{1}{\\rho} \\qquad\\Longleftrightarrow\\qquad \\rho = \\frac{1}{\\sigma}

Symbols and SI units:

  • rho\\rho — resistivity, ohm-metres (Ω·m)
  • sigma\\sigma — conductivity, siemens per metre (S/m); one siemens is one reciprocal ohm

There is no constant of proportionality and no unit juggling: 1/(Omegacdottextm)1/(\\Omega\\cdot\\text{m}) is S/m. Copper at 20 °C sits at rho=1.68times108\\rho = 1.68 \\times 10^{-8} Ω·m, so sigma=5.96times107\\sigma = 5.96 \\times 10^{7} S/m.

Conductor metals are often quoted as a percentage of the International Annealed Copper Standard, \\%\\text{IACS} = \\sigma / (5.80 \\times 10^{7}\\ \\text{S/m}) \\times 100.

The operating assumption: a homogeneous, isotropic material at a stated temperature. Both quantities drift with temperature, so a value without a temperature is incomplete.

Getting Resistance Out of Resistivity

Resistivity becomes a resistance once you add the geometry:

R=fracrhoLA=fracLsigmaAqquadLongrightarrowqquadrho=fracRALR = \\frac{\\rho L}{A} = \\frac{L}{\\sigma A} \\qquad\\Longrightarrow\\qquad \\rho = \\frac{RA}{L}

with RR in ohms, LL in metres and AA in square metres. The last form is how resistivity is measured in practice: take a sample of known length and cross-section, measure its resistance, and divide.

Temperature is handled with a linear coefficient about a reference temperature T0T_0:

rhoT=rho0left[1+alpha(TT0)right]\\rho_T = \\rho_{0}\\left[1 + \\alpha (T - T_0)\\right]

For copper, alphaapprox0.00393\\alpha \\approx 0.00393 per °C referenced to 20 °C.

Watch the units people trip on. Water and process conductivity is quoted in µS/cm, not S/m; 11 S/m =10,000= 10{,}000 µS/cm. Cable tables often use Ω·mm²/m, where copper is 0.01680.0168 — numerically the same as 1.68times1081.68 \\times 10^{-8} Ω·m, because 11 Ω·mm²/m =106= 10^{-6} Ω·m.

The mistake people make: measuring a two-wire loop and dividing by the one-way length. Use the full conductor length the current actually travels.

Common Mistakes to Avoid

  • Inverting the wrong quantity — a small resistivity means a large conductivity. If rho=108\\rho = 10^{-8} gives sigma=108\\sigma = 10^{-8}, a reciprocal was skipped.
  • Mixing µS/cm with S/m — divide µS/cm by 10,00010{,}000 to get S/m before inverting.
  • Using mm² for AA in an SI formula1010 mm² is 1times1051 \\times 10^{-5} m², a factor of a million.
  • Ignoring temperature — a conductor running at 7575 °C has about 2222\\% more resistance than the same conductor at 2020 °C, which matters for voltage-drop work.
  • Treating resistivity as a fixed constant for an alloy — it varies with composition, temper and impurity level, so use the supplier's figure for the actual material.
  • Confusing resistivity with sheet resistance — sheet resistance is rho/t\\rho/t in ohms per square and applies to a thin film of thickness tt.

示例题目

Step 1: rho=1/sigma\\rho = 1/\\sigma
Step 2: rho=1div(5.96times107textS/m)\\rho = 1 \\div (5.96 \\times 10^{7}\\ \\text{S/m})
Step 3: rho=1.678times108Omegacdottextm\\rho = 1.678 \\times 10^{-8}\\ \\Omega\\cdot\\text{m}
Step 4: The unit follows directly: the reciprocal of S/m is Ω·m
Answer: rhoapprox1.68times108\\rho \\approx 1.68 \\times 10^{-8} Ω·m

Step 1: sigma=1/rho=1div(2.65times108Omegacdottextm)=3.774times107textS/m\\sigma = 1/\\rho = 1 \\div (2.65 \\times 10^{-8}\\ \\Omega\\cdot\\text{m}) = 3.774 \\times 10^{7}\\ \\text{S/m}
Step 2: IACS reference: sigmatextIACS=5.80times107textS/m\\sigma_{\\text{IACS}} = 5.80 \\times 10^{7}\\ \\text{S/m}
Step 3: \\%\\text{IACS} = (3.774 \\times 10^{7}) \\div (5.80 \\times 10^{7}) \\times 100
Step 4: =0.651times100=65.1= 0.651 \\times 100 = 65.1\\%
Answer: sigmaapprox3.77times107\\sigma \\approx 3.77 \\times 10^{7} S/m, about 6565\\% IACS

Step 1: Cross-section: A=pid2/4=pi(1.024times103textm)2/4A = \\pi d^2/4 = \\pi (1.024 \\times 10^{-3}\\ \\text{m})^2/4
Step 2: =pi(1.0486times106textm2)/4=8.235times107textm2= \\pi (1.0486 \\times 10^{-6}\\ \\text{m}^2)/4 = 8.235 \\times 10^{-7}\\ \\text{m}^2
Step 3: rho=RA/L=(0.61Omega)(8.235times107textm2)div(30textm)\\rho = RA/L = (0.61\\ \\Omega)(8.235 \\times 10^{-7}\\ \\text{m}^2) \\div (30\\ \\text{m})
Step 4: Numerator: 5.023times107Omegacdottextm25.023 \\times 10^{-7}\\ \\Omega\\cdot\\text{m}^2
Step 5: rho=(5.023times107)div30=1.674times108Omegacdottextm\\rho = (5.023 \\times 10^{-7}) \\div 30 = 1.674 \\times 10^{-8}\\ \\Omega\\cdot\\text{m}
Step 6: sigma=1/rho=5.97times107textS/m\\sigma = 1/\\rho = 5.97 \\times 10^{7}\\ \\text{S/m} — consistent with copper at 20 °C
Answer: rhoapprox1.67times108\\rho \\approx 1.67 \\times 10^{-8} Ω·m, sigmaapprox5.97times107\\sigma \\approx 5.97 \\times 10^{7} S/m

常见问题

Take the reciprocal: rho = 1/sigma. If sigma is in siemens per metre the answer comes out directly in ohm-metres, because one siemens is one reciprocal ohm. No extra constant is involved.

Measure its resistance R, its length L and its diameter, work out the cross-sectional area A = pi d squared / 4 in square metres, then use rho = RA/L. Quote the temperature with the result, since resistivity changes with it.

Use R = rho L / A, with the resistivity in ohm-metres, the length in metres and the area in square metres. Equivalently R = L/(sigma A) if you have the conductivity instead.

Divide by 10,000. Water quality instruments read in uS/cm, so 500 uS/cm is 0.05 S/m, which inverts to a resistivity of 20 ohm-metres. Convert first, then take the reciprocal.

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