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Trigonometry · real student question

Given sin(theta) = 0.66, find the angle theta in degrees and in radians.

Question

Given

sin⁡θ=0.66\sin\theta=0.66

find θ\theta in degrees and in radians.

Step-by-step solution

  1. Take the inverse sine of both sides.

    θ=sin⁡−1(0.66)\theta=\sin^{-1}(0.66)

    The principal value lies in [−90∘,90∘][-90^\circ,90^\circ], and since 0.66>00.66>0 the angle is acute.

  2. Check the domain. ∣0.66∣≤1|0.66|\le1, so the inverse sine is defined.

  3. Estimate before computing. 0.660.66 sits between sin⁡30∘=0.5\sin30^\circ=0.5 and sin⁡45∘≈0.7071\sin45^\circ\approx0.7071, so expect an angle in the low 40∘40^\circs.

  4. Evaluate in degrees.

    θ=sin⁡−1(0.66)=41.2999∘≈41.30∘\theta=\sin^{-1}(0.66)=41.2999^\circ\approx41.30^\circ

  5. Convert to radians.

    41.2999×π180=0.7208 rad41.2999\times\frac{\pi}{180}=0.7208\ \text{rad}

  6. Observe the sensitivity, then verify. Comparing with sin⁡−1(0.67)=42.07∘\sin^{-1}(0.67)=42.07^\circ: a change of just 0.010.01 in the sine shifts the angle by about 0.77∘0.77^\circ. That amplification is why inverse-trig inputs should be carried to full precision rather than rounded early. Checking backwards, sin⁡(0.7208188)=0.660000\sin(0.7208188)=0.660000 ✓.

Answer

θ=sin⁡−1(0.66)≈41.30∘≈0.7208 rad\theta=\sin^{-1}(0.66)\approx 41.30^\circ\approx 0.7208\ \text{rad}

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