Geometry · real student question

A sonographer measures a gallstone as a sphere of diameter 12 millimetres. What is its volume?

Question

A gallstone is modelled as a sphere of diameter 1212 mm. Find its volume.

Step-by-step solution

  1. Convert diameter to radius first. The sphere formula takes the radius, and using 1212 in place of 66 would inflate the answer by a factor of 23=82^3=8:

    r=d2=122=6 mmr=\frac{d}{2}=\frac{12}{2}=6\ \text{mm}

  2. Write the volume formula.

    V=43πr3V=\frac{4}{3}\pi r^{3}

  3. Cube the radius and substitute.

    63=216,V=43π(216)=288π mm36^{3}=216,\qquad V=\frac{4}{3}\pi(216)=288\pi\ \text{mm}^3

    Keeping 288π288\pi exact until the end avoids compounding rounding error.

  4. Convert to a decimal. With the true value of π\pi,

    V=288π904.779 mm3V=288\pi\approx 904.779\ \text{mm}^3

    288π904.8 mm3\boxed{288\pi\approx 904.8\ \text{mm}^3}

  5. Reconcile with the printed answer key. Many textbooks use the approximation π3.14\pi\approx 3.14, which gives 288×3.14=904.32 mm3288\times 3.14=904.32\ \text{mm}^3 — that is why an option of 904.32904.32 appears rather than 904.78904.78. Both come from the same 288π288\pi; the difference is purely the value substituted for π\pi, so quote 288π288\pi if an exact answer is allowed.

  6. Sanity-check the unit conversion. Since 1 cm=10 mm1\ \text{cm}=10\ \text{mm}, one cubic centimetre is 1000 mm31000\ \text{mm}^3, so the stone is about 0.9 cm30.9\ \text{cm}^3 — which rules out any option quoted as several cubic centimetres.

Answer

V=288π904.8 mm3 (904.32 mm3 if π=3.14)V=288\pi\approx 904.8\ \text{mm}^3\ (\approx 904.32\ \text{mm}^3\text{ if }\pi=3.14)

Need to solve a different problem like this? Open the solver →