Geometry · real student question

Find the volume of a regular square pyramid whose square base has edge 15 m and whose height is 8 m.

Question

Find the volume of the regular square pyramid whose square base has edge 15 m15\ \text{m} and whose height is 8 m8\ \text{m}.

V=[ ? ] m3V=[\ ?\ ]\ \text{m}^3

Step-by-step solution

  1. Write the pyramid volume formula. For any pyramid, whatever the base shape,

    V=13Bh,V=\frac{1}{3}Bh,

    where BB is the area of the base and hh is the perpendicular height from the apex to the base plane.

  2. Compute the base area. The base is a square of edge 15 m15\ \text{m}:

    B=152=225 m2.B=15^{2}=225\ \text{m}^2.

  3. Substitute the height. The height given is h=8 mh=8\ \text{m}. Take care not to confuse this with the slant height, which runs along a triangular face and would be longer; only the perpendicular height belongs in this formula.

  4. Multiply and divide by three.

    V=13(225)(8)=18003=600 m3.V=\frac{1}{3}(225)(8)=\frac{1800}{3}=600\ \text{m}^3.

  5. Interpret the one third. A prism on the same square base with the same height would hold 225×8=1800 m3225\times 8=1800\ \text{m}^3; the pyramid holds exactly one third of that, 600 m3600\ \text{m}^3. Checking that your pyramid answer is one third of the matching prism is a fast way to catch a dropped factor.

Answer

V=13(152)(8)=600 m3V=\frac{1}{3}(15^{2})(8)=600\ \text{m}^{3}

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