Geometry · real student question

The diameter of a ball is 6 inches. What is the volume of the ball? Choose from 12.76, 37.68, 113.04 or 676.91 cubic inches.

Question

The diameter of a ball is 66 inches. What is the volume of the ball?

A) 12.76 in312.76\ \text{in}^3 B) 37.68 in337.68\ \text{in}^3 C) 113.04 in3113.04\ \text{in}^3 D) 676.91 in3676.91\ \text{in}^3

Step-by-step solution

  1. Convert the diameter to a radius before opening the formula. The volume formula is written in terms of rr, and the problem hands you dd:

    r=d2=62=3 in.r=\frac{d}{2}=\frac{6}{2}=3\ \text{in}.

    Skipping this step is the trap: using 66 in place of 33 multiplies the answer by 23=82^3=8, which is exactly how the distractor 904904-sized values are generated.

  2. State the formula for the volume of a sphere.

    V=43πr3.V=\frac{4}{3}\pi r^{3}.

  3. Cube the radius, then multiply.

    r3=33=27,V=43π27=1083π=36π in3.r^{3}=3^{3}=27,\qquad V=\frac{4}{3}\pi\cdot 27=\frac{108}{3}\pi=36\pi\ \text{in}^3.

    The 33 in the denominator divides into 2727 cleanly, so no decimals are needed yet.

  4. Evaluate numerically. With π3.14159\pi\approx 3.14159,

    V=36π113.10 in3,V=36\pi\approx 113.10\ \text{in}^3,

    and with the classroom value π=3.14\pi=3.14 the same product is 36×3.14=113.04 in336\times 3.14=113.04\ \text{in}^3. That is choice C — the small gap between 113.04113.04 and 113.10113.10 is purely the rounding of π\pi, not an error.

  5. Rule out the other options. 37.68=12π37.68=12\pi is 4πr2/4\pi r^2/\ldots — in fact it is 43πr3\tfrac43\pi r^3 computed with r3r^3 replaced by rr; 12.7612.76 is far too small for a ball three inches in radius; and 676.91676.91 is roughly 43π63/\tfrac43\pi\cdot 6^3/\ldots, the value you get by forgetting to halve the diameter. Only C survives.

Answer

V=43π(3)3=36π113.1 in3(choice C, 113.04 with π=3.14)V=\frac{4}{3}\pi(3)^{3}=36\pi\approx 113.1\ \text{in}^{3}\quad(\text{choice C, }113.04\text{ with }\pi=3.14)

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