Geometry · real student question

If LM = 14, MN = x + 18, and LN = 3x − 6, what is LN?

Question

Point MM lies between LL and NN on a line. If

LM=14,MN=x+18,LN=3x6,LM = 14, \qquad MN = x + 18, \qquad LN = 3x - 6,

what is LNLN?

Step-by-step solution

  1. Write the segment addition relation. With MM between LL and NN, the two adjacent pieces sum to the whole segment:

    LM+MN=LNLM + MN = LN

    The whole segment LNLN is the one whose endpoints are the two outer points, so it belongs on its own side.

  2. Substitute the given expressions.

    14+(x+18)=3x614 + (x + 18) = 3x - 6

    One length is a plain number and two are expressions in xx; that is fine, the equation still has a single unknown.

  3. Simplify the left side.

    x+32=3x6x + 32 = 3x - 6

  4. Solve for x. Gather the xx terms on the right and the constants on the left:

    32+6=3xx  38=2x  x=1932 + 6 = 3x - x \ \Longrightarrow \ 38 = 2x \ \Longrightarrow \ x = 19

  5. Substitute into the requested length. The question asks for LNLN, so use its expression:

    LN=3(19)6=576=51LN = 3(19) - 6 = 57 - 6 = 51

  6. Verify the whole picture. With x=19x = 19: LM=14LM = 14, MN=19+18=37MN = 19 + 18 = 37, and 14+37=51=LN14 + 37 = 51 = LN. Every length is positive and the sum checks, so LN=51LN = 51.

Answer

LN=51LN = 51

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