Calculus · real student question

Evaluate the limit of (5x^3 - 2x + 1)/(3x^3 + 7) as x approaches infinity.

Question

Evaluate

limx5x32x+13x3+7.\lim_{x\to\infty}\frac{5x^{3}-2x+1}{3x^{3}+7}.

Step-by-step solution

  1. Diagnose the indeterminate form. As xx\to\infty the numerator and denominator both grow without bound, giving \tfrac{\infty}{\infty}. That is not a value — it only tells you the expression must be rewritten before the limit can be read off.

  2. Divide numerator and denominator by the highest power present. Both are cubic, so divide every term by x3x^3 (legitimate for large xx, where x0x\neq 0):

    5x32x+13x3+7=52x2+1x33+7x3.\frac{5x^{3}-2x+1}{3x^{3}+7}=\frac{5-\dfrac{2}{x^{2}}+\dfrac{1}{x^{3}}}{3+\dfrac{7}{x^{3}}}.

  3. Send each reciprocal power to zero. For any k>0k>0, 1xk0\dfrac{1}{x^{k}}\to 0 as xx\to\infty, so the three small terms disappear:

    limx50+03+0=53.\lim_{x\to\infty}\frac{5-0+0}{3+0}=\frac{5}{3}.

  4. State the general rule this illustrates. For a rational function, compare the degrees: equal degrees give the ratio of leading coefficients (here 53\tfrac53), a smaller numerator degree gives 00, and a larger numerator degree gives ±\pm\infty. The lower-order terms 2x-2x, +1+1 and +7+7 never affect the answer.

  5. Check numerically. At x=106x=10^{6} the quotient is

    510182106+131018+7=1.6666666,\frac{5\cdot 10^{18}-2\cdot 10^{6}+1}{3\cdot 10^{18}+7}=1.6666666\ldots,

    agreeing with 53=1.66\tfrac53=1.6\overline{6} to many decimal places.

Answer

53\frac{5}{3}

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