Algebra · real student question

Solve for y: (y + 397)/(−409 + 397) = (x − 362)/(366 − 362).

Question

Write

y+397409+397=x362366362\frac{y + 397}{-409 + 397} = \frac{x - 362}{366 - 362}

in slope-intercept form.

Step-by-step solution

  1. Recognise the two-point form. The layout

    yy1y2y1=xx1x2x1\frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1}

    matches with (x1,y1)=(362,397)(x_1, y_1) = (362, -397) and (x2,y2)=(366,409)(x_2, y_2) = (366, -409): the numerator y+397y + 397 is y(397)y - (-397), and 409+397-409 + 397 is y2y1y_2 - y_1. So this is the line through those two points.

  2. Simplify both denominators first.

    409+397=12,366362=4-409 + 397 = -12, \qquad 366 - 362 = 4

    so the equation is

    y+39712=x3624\frac{y + 397}{-12} = \frac{x - 362}{4}

    The slope is already visible: m=y2y1x2x1=124=3m = \dfrac{y_2 - y_1}{x_2 - x_1} = \dfrac{-12}{4} = -3.

  3. Cross-multiply.

    4(y+397)=12(x362)4(y + 397) = -12(x - 362)

    Keep the negative sign attached to the 1212; dropping it flips the slope and is the most common error in this rearrangement.

  4. Expand both sides.

    4y+1588=12x+43444y + 1588 = -12x + 4344

    Here 4×397=15884 \times 397 = 1588 and 12×362=434412 \times 362 = 4344.

  5. Isolate y.

    4y=12x+43441588=12x+27564y = -12x + 4344 - 1588 = -12x + 2756

    y=3x+689y = -3x + 689

  6. Check both original points lie on the line. At x=362x = 362: y=1086+689=397 y = -1086 + 689 = -397 \ \checkmark. At x=366x = 366: y=1098+689=409 y = -1098 + 689 = -409 \ \checkmark. The slope 3-3 agrees with the rise over run computed in step 2, so the conversion is correct.

Answer

y=3x+689y = -3x + 689

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