Algebra · real student question

Write a linear equation for the line that passes through the point (−1, 7) and has slope m = −4.

Question

Write an equation for the line through the point (1,7)(-1, 7) with slope m=4m = -4.

Step-by-step solution

  1. Choose the form that uses a point and a slope directly. Point-slope form is built for exactly this data:

    yy1=m(xx1)y - y_1 = m(x - x_1)

    where (x1,y1)(x_1, y_1) is the known point and mm the slope. Nothing has to be solved for first.

  2. Substitute, and handle the negative x-coordinate carefully. With (x1,y1)=(1,7)(x_1, y_1) = (-1, 7) and m=4m = -4:

    y7=4(x(1))=4(x+1)y - 7 = -4\bigl(x - (-1)\bigr) = -4(x + 1)

    The subtraction of a negative coordinate turns into addition. Writing 4(x1)-4(x - 1) here is the most common slip and would give the wrong intercept.

  3. Distribute the slope.

    y7=4x4y - 7 = -4x - 4

  4. Isolate y to reach slope-intercept form. Adding 77 to both sides:

    y=4x4+7=4x+3y = -4x - 4 + 7 = -4x + 3

    So the slope is 4-4 (as required) and the y-intercept is 33.

  5. Check that the original point satisfies the equation. Substituting x=1x = -1:

    y=4(1)+3=4+3=7 y = -4(-1) + 3 = 4 + 3 = 7 \ \checkmark

    The point lies on the line and the coefficient of xx is the given slope, so both conditions hold. In standard form the same line is 4x+y=34x + y = 3.

Answer

y=4x+3y = -4x + 3

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