Algebra · real student question

Solve for x: x - (0.8x - 5000)(0.03) = 6494.

Question

Solve for xx:

x(0.8x5000)(0.03)=6494.x-\left(0.8x-5000\right)\left(0.03\right)=6494.

Step-by-step solution

  1. Read the structure. A quantity xx has a deduction taken from it, and the deduction is 3%3\% of an adjusted base 0.8x50000.8x-5000 rather than of xx itself. That nesting is the only thing that makes this harder than a one-step problem, and it is why the final coefficient will not be a round 0.970.97.

  2. Expand the product. Multiplying out the bracket:

    0.03(0.8x5000)=0.024x150.0.03\,(0.8x-5000)=0.024x-150.

    Check both pieces: 0.03×0.8=0.0240.03\times0.8=0.024 and 0.03×5000=1500.03\times5000=150. Getting 0.0240.024 right — three decimal places, not two — is essential.

  3. Distribute the minus sign. The whole product is subtracted, so both of its terms flip:

    x(0.024x150)=x0.024x+150.x-\left(0.024x-150\right)=x-0.024x+150.

    The 150-150 becomes +150+150; treating the deduction as a flat subtraction of 150150 instead is the most common error here.

  4. Combine like terms and solve. Since 10.024=0.9761-0.024=0.976:

    0.976x+150=6494    0.976x=6344    x=63440.976=6500.0.976x+150=6494\;\Longrightarrow\;0.976x=6344\;\Longrightarrow\;x=\frac{6344}{0.976}=6500.

    The division comes out exactly: 0.976×6500=63440.976\times6500=6344, so no rounding is involved and the answer is a clean whole number.

  5. Substitute back into the original equation. The adjusted base is 0.8(6500)5000=52005000=2000.8(6500)-5000=5200-5000=200, the deduction is 0.03×200=60.03\times200=6, and

    65006=6494.6500-6=6494 ✓.

    The deduction being just 66 explains why xx ends up so close to the target value — worth noticing as a plausibility check before doing any arithmetic.

Answer

x=63440.976=6500x=\frac{6344}{0.976}=6500

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