Algebra · real student question

Solve (x − 1) × 0.6 + 3 = 51203.3 for x, giving an exact value.

Question

Solve for xx:

(x1)0.6+3=51203.3(x-1)\cdot 0.6 + 3 = 51203.3

Step-by-step solution

  1. Undo the addition first. Working outward from the constant term:

    (x1)0.6=51203.33=51200.3(x-1)\cdot 0.6 = 51203.3 - 3 = 51200.3

    The bracket is treated as one block — there is no need to expand 0.6x0.60.6x - 0.6 at this stage.

  2. Divide by 0.6 as a fraction, not a decimal. Since 0.6=350.6 = \tfrac{3}{5}, dividing by it means multiplying by 53\tfrac{5}{3}:

    x1=51200.30.6=5120031053=5120036x - 1 = \frac{51200.3}{0.6} = \frac{512003}{10}\cdot\frac{5}{3} = \frac{512003}{6}

    Going through fractions is what keeps the answer exact; 512003512003 is not divisible by 33 (its digits sum to 1111), so the fraction will not terminate as a decimal.

  3. Add 1 to isolate x. Writing 1=661 = \tfrac66:

    x=5120036+66=5120096x = \frac{512003}{6} + \frac{6}{6} = \frac{512009}{6}

  4. Convert to a decimal. Long division gives

    x=5120096=85334.8385334.8333x = \frac{512009}{6} = 85334.8\overline{3} \approx 85334.8333

    The repeating 33 is unavoidable, which is why the fractional form is the honest "exact answer".

  5. Substitute back to verify exactly.

    (51200961)35+3=512003635+3=51200310+3=51200.3+3=51203.3 \left(\frac{512009}{6} - 1\right)\cdot\frac{3}{5} + 3 = \frac{512003}{6}\cdot\frac{3}{5} + 3 = \frac{512003}{10} + 3 = 51200.3 + 3 = 51203.3 \ \checkmark

    The check closes with no rounding at all, which a decimal-only route could not demonstrate.

Answer

x=5120096=85334.8385334.8333x = \frac{512009}{6} = 85334.8\overline{3} \approx 85334.8333

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