Algebra · real student question

Solve the system 220x + 100y = 960 and x + y = 6.

Question

Solve the system

220x+100y=960,x+y=6220x+100y=960,\qquad x+y=6

Step-by-step solution

  1. Pick the easier equation to rearrange. The second equation has unit coefficients, so solving it for one variable costs nothing:

    y=6xy=6-x

    Choosing this direction avoids fractions entirely — rearranging the first equation instead would give y=(960220x)/100y=(960-220x)/100.

  2. Substitute into the first equation.

    220x+100(6x)=960220x+100(6-x)=960

    One equation in one unknown is now all that is left.

  3. Expand and combine.

    220x+600100x=960120x+600=960220x+600-100x=960\quad\Rightarrow\quad 120x+600=960

    The coefficient 120=220100120=220-100 is the difference of the two unit values, which is why a small change in xx moves the total so slowly.

  4. Solve for xx, then back-substitute.

    120x=360x=3,y=63=3120x=360\quad\Rightarrow\quad x=3,\qquad y=6-3=3

  5. Check both equations, and sanity-check by average. First: 220(3)+100(3)=660+300=960220(3)+100(3)=660+300=960 ✓. Second: 3+3=63+3=6 ✓. As a structural check, the mean value per unit is 960/6=160960/6=160, exactly halfway between 220220 and 100100 — which forces an equal split, as found.

Answer

x=3,y=3x=3,\qquad y=3

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