Algebra · real student question

Solve the system: X * 4.50 + Y * 4.95 = 2368.15 and X + Y = 490.5.

Question

Solve the system

4.50X+4.95Y=2368.15,X+Y=490.54.50X+4.95Y=2368.15,\qquad X+Y=490.5

Step-by-step solution

  1. Solve the simple equation for one variable. The total equation rearranges with no arithmetic at all:

    X=490.5YX=490.5-Y

    Substitution is the natural choice whenever one equation already has a variable with coefficient 11.

  2. Substitute into the value equation.

    4.50(490.5Y)+4.95Y=2368.154.50(490.5-Y)+4.95Y=2368.15

    2207.254.50Y+4.95Y=2368.152207.25-4.50Y+4.95Y=2368.15

  3. Collect and solve for YY. The YY coefficient is the price gap 4.954.50=0.454.95-4.50=0.45:

    0.45Y=2368.152207.25=160.90    Y=160.900.45=1609045=32189357.560.45Y=2368.15-2207.25=160.90\;\Longrightarrow\;Y=\frac{160.90}{0.45}=\frac{16090}{45}=\frac{3218}{9}\approx 357.56

  4. Recover XX from the substitution.

    X=490.532189=4414.532189=239318132.94X=490.5-\frac{3218}{9}=\frac{4414.5-3218}{9}=\frac{2393}{18}\approx 132.94

    Keeping 239318\tfrac{2393}{18} rather than a rounded decimal matters if the answer feeds into further calculation.

  5. Verify both equations. Sum: 239318+32189=2393+643618=882918=490.5  \tfrac{2393}{18}+\tfrac{3218}{9}=\tfrac{2393+6436}{18}=\tfrac{8829}{18}=490.5\;\checkmark. Value: 4.50239318+4.9532189=10768.518+15929.19=598.25+1769.90=2368.15  4.50\cdot\tfrac{2393}{18}+4.95\cdot\tfrac{3218}{9}=\tfrac{10768.5}{18}+\tfrac{15929.1}{9}=598.25+1769.90=2368.15\;\checkmark.

Answer

X=239318132.94,Y=32189357.56X=\frac{2393}{18}\approx 132.94,\qquad Y=\frac{3218}{9}\approx 357.56

Need to solve a different problem like this? Open the solver →