Algebra · real student question

Solve for x: (3.75 x 98) + 4x = 3.8 x (98 + x).

Question

Solve for xx:

(3.75×98)+4x=3.8×(98+x).(3.75\times98)+4x=3.8\times(98+x).

Step-by-step solution

  1. Read what the equation says. A quantity of 9898 units at grade 3.753.75 is blended with xx units at grade 44, and the result must average 3.83.8 across all 98+x98+x units. Because 3.83.8 lies much closer to 3.753.75 than to 44, the answer should be a fairly small xx — a useful expectation to hold before computing.

  2. Evaluate the constants and expand. On the left, 3.75×98=367.53.75\times98=367.5. On the right, distribute:

    3.8×(98+x)=3.8×98+3.8x=372.4+3.8x.3.8\times(98+x)=3.8\times98+3.8x=372.4+3.8x.

    Check the two products: 3.75×98=3.75×1003.75×2=3757.5=367.53.75\times98=3.75\times100-3.75\times2=375-7.5=367.5 ✓, and 3.8×98=3807.6=372.43.8\times98=380-7.6=372.4 ✓.

  3. Collect the xx terms. The equation is 367.5+4x=372.4+3.8x367.5+4x=372.4+3.8x. Subtracting 3.8x3.8x from both sides:

    367.5+0.2x=372.4.367.5+0.2x=372.4.

    The coefficient 0.2=43.80.2=4-3.8 is the gap between the new material's grade and the target grade — that small number is why xx ends up much larger than the constant difference.

  4. Isolate and solve. Subtracting 367.5367.5:

    0.2x=4.9    x=4.90.2=24.5.0.2x=4.9\;\Longrightarrow\;x=\frac{4.9}{0.2}=24.5.

    Dividing by 0.20.2 is multiplying by 55, so 4.9×5=24.54.9\times5=24.5 — no long division required.

  5. Check both sides of the original equation. Left: 367.5+4(24.5)=367.5+98=465.5367.5+4(24.5)=367.5+98=465.5. Right: 3.8×(98+24.5)=3.8×122.5=465.53.8\times(98+24.5)=3.8\times122.5=465.5 ✓. The blend contains 24.524.5 units of the richer material against 9898 of the poorer, which matches the expectation from step 1 that xx would be a modest fraction of 9898.

Answer

x=4.90.2=24.5x=\frac{4.9}{0.2}=24.5

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