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Algebra · real student question

Solve for x: 8/(8.9 - x) = (71 - x times root((8.9 - x)^2 - 64)/(8.9 - x))/71.

Question

Solve for xx:

88.9−x=71−x(8.9−x)2−648.9−x71\frac{8}{8.9-x}=\frac{71-\dfrac{x\sqrt{(8.9-x)^2-64}}{8.9-x}}{71}

Step-by-step solution

  1. Fix the domain first. We need 8.9−x≠08.9-x\neq0 and (8.9−x)2−64≥0(8.9-x)^2-64\ge0, i.e. ∣8.9−x∣≥8|8.9-x|\ge8, which means

    x≤0.9orx≥16.9x\le 0.9\qquad\text{or}\qquad x\ge 16.9

    Every candidate root must survive this test, and squaring later will manufacture roots that do not.

  2. Clear both denominators. Multiplying by 7171 and then by 8.9−x8.9-x:

    568=71(8.9−x)−x(8.9−x)2−64568=71(8.9-x)-x\sqrt{(8.9-x)^2-64}

    Since 71(8.9)=631.971(8.9)=631.9, this rearranges to

    x(8.9−x)2−64=631.9−71x−568=63.9−71xx\sqrt{(8.9-x)^2-64}=631.9-71x-568=63.9-71x

  3. Factor the radicand as a difference of squares. This is the step that makes the problem tractable:

    (8.9−x)2−64=(8.9−x−8)(8.9−x+8)=(0.9−x)(16.9−x)(8.9-x)^2-64=(8.9-x-8)(8.9-x+8)=(0.9-x)(16.9-x)

    and at the same time 63.9−71x=71(0.9−x)63.9-71x=71(0.9-x). The same factor 0.9−x0.9-x appears on both sides, so the equation is

    x(0.9−x)(16.9−x)=71(0.9−x)x\sqrt{(0.9-x)(16.9-x)}=71(0.9-x)

  4. Read off the first solution for free. If 0.9−x=00.9-x=0 both sides are zero, so x=0.9x=0.9 is an exact solution. Checking in the original: 88=1\tfrac{8}{8}=1 on the left, and on the right the radical is 00, giving 71−071=1\tfrac{71-0}{71}=1 ✓.

  5. Handle the remaining branch. For x<0.9x<0.9 we have 0.9−x>00.9-x>0, so (0.9−x)(16.9−x)=0.9−x 16.9−x\sqrt{(0.9-x)(16.9-x)}=\sqrt{0.9-x}\,\sqrt{16.9-x} and one factor of 0.9−x\sqrt{0.9-x} cancels:

    x16.9−x=710.9−x ⟹ x2(16.9−x)=5041(0.9−x)x\sqrt{16.9-x}=71\sqrt{0.9-x}\ \Longrightarrow\ x^{2}(16.9-x)=5041(0.9-x)

    ⟹ x3−16.9x2−5041x+4536.9=0\Longrightarrow\ x^{3}-16.9x^{2}-5041x+4536.9=0

    (The branch x≥16.9x\ge16.9 is impossible: there the left side is ≥0\ge0 while 71(0.9−x)<071(0.9-x)<0.)

  6. Solve the cubic and reject the extraneous roots. Its roots are −63.5486-63.5486, 0.89744330.8974433 and 79.551179.5511. Squaring required x>0x>0 and x≤0.9x\le0.9, so the first and third are extraneous - substituting them into the original equation gives −1.78-1.78 and −2.23-2.23 instead of 00. Only

    x=0.8974433x=0.8974433

    survives, and it reproduces the original equation to 10−810^{-8} ✓.

  7. State both answers. The full solution set is x=0.9x=0.9 and x≈0.8974433x\approx0.8974433. Note (x−0.9)(x-0.9) times the cubic reproduces the quartic x4−17.8x3−5025.79x2+9073.8x−4083.21x^4-17.8x^3-5025.79x^2+9073.8x-4083.21 exactly, confirming no root was lost.

Answer

x=0.9andx≈0.8974433x=0.9\quad\text{and}\quad x\approx 0.8974433

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