Algebra · real student question

Solve for x: 1600W times 8% + 1600W times 2% + 3200W times 0.0006 + 0.13x + 3200W times 1% = x.

Question

Solve for xx:

1600W8%+1600W2%+3200W0.0006+0.13x+3200W1%=x1600W\cdot 8\%+1600W\cdot 2\%+3200W\cdot 0.0006+0.13x+3200W\cdot 1\%=x

Here WW is a constant carried through the calculation.

Step-by-step solution

  1. Convert the percentages and note what kind of equation this is. Replacing 8%=0.088\%=0.08, 2%=0.022\%=0.02, 1%=0.011\%=0.01 leaves xx on both sides. That makes it a linear equation to be solved, not an expression to be evaluated - the 0.13x0.13x term cannot simply be added up with the constants.

  2. Evaluate each constant term separately.

    1600W(0.08)=128W,1600W(0.02)=32W1600W(0.08)=128W,\quad 1600W(0.02)=32W

    3200W(0.0006)=1.92W,3200W(0.01)=32W3200W(0.0006)=1.92W,\quad 3200W(0.01)=32W

  3. Add the constant terms.

    128W+32W+1.92W+32W=193.92W128W+32W+1.92W+32W=193.92W

    so the equation reads 193.92W+0.13x=x193.92W+0.13x=x.

  4. Collect the xx terms on one side. Subtracting 0.13x0.13x from both sides:

    193.92W=x0.13x=0.87x193.92W=x-0.13x=0.87x

    The coefficient 0.87=10.130.87=1-0.13 is the point of the whole problem: only 87%87\% of xx is left over to balance the fixed losses.

  5. Divide by 0.870.87.

    x=193.92W0.87=222.8966Wx=\frac{193.92W}{0.87}=222.8966W

  6. Substitute back to check. With x=222.8966Wx=222.8966W, the left side is 193.92W+0.13(222.8966W)=193.92W+28.9766W=222.8966W193.92W+0.13(222.8966W)=193.92W+28.9766W=222.8966W, which equals the right side ✓.

Answer

x=193.92W0.87222.90Wx=\frac{193.92W}{0.87}\approx 222.90W

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