Algebra · real student question

Solve -4.6173x^2 - 0.2906x + 20.029 = 0 for x.

Question

Solve

y=4.6173x20.2906x+20.029y=-4.6173x^2-0.2906x+20.029

for the values of xx where y=0y=0.

Step-by-step solution

  1. Clear the negative leading coefficient. Multiplying an equation by 1-1 changes no roots but removes the most error-prone sign:

    4.6173x20.2906x+20.029=0    4.6173x2+0.2906x20.029=0-4.6173x^2-0.2906x+20.029=0\iff 4.6173x^2+0.2906x-20.029=0

    Now a=4.6173a=4.6173, b=0.2906b=0.2906, c=20.029c=-20.029, and the denominator 2a2a in the quadratic formula is positive.

  2. Compute the discriminant.

    Δ=b24ac=0.0844484(4.6173)(20.029)=0.084448+369.9196=370.00406\Delta=b^2-4ac=0.084448-4(4.6173)(-20.029)=0.084448+369.9196=370.00406

    Δ=19.23548\sqrt{\Delta}=19.23548

    The negative cc guarantees 4ac>0-4ac>0, so two real roots of opposite signs are certain before any further work.

  3. Apply the quadratic formula.

    x=0.2906±19.235482(4.6173)=0.2906±19.235489.2346x=\frac{-0.2906\pm 19.23548}{2(4.6173)}=\frac{-0.2906\pm 19.23548}{9.2346}

  4. Evaluate both roots.

    x1=0.290619.235489.2346=2.11445,x2=0.2906+19.235489.2346=2.05151x_1=\frac{-0.2906-19.23548}{9.2346}=-2.11445,\qquad x_2=\frac{-0.2906+19.23548}{9.2346}=2.05151

    With the positive leading coefficient the plus branch now gives the larger root, as intuition expects.

  5. Verify by substitution and by Vieta. Putting x=2.05151x=2.05151 into the original: 4.6173(4.20869)0.2906(2.05151)+20.029=19.43310.5962+20.0290  -4.6173(4.20869)-0.2906(2.05151)+20.029=-19.4331-0.5962+20.029\approx 0\;\checkmark. Vieta: the sum should be 0.29064.6173=0.06294-\tfrac{0.2906}{4.6173}=-0.06294 and 2.11445+2.05151=0.06294  -2.11445+2.05151=-0.06294\;\checkmark; the product should be 20.0294.6173=4.33780\tfrac{-20.029}{4.6173}=-4.33780 and (2.11445)(2.05151)=4.33782  (-2.11445)(2.05151)=-4.33782\;\checkmark.

Answer

x2.1144andx2.0515x\approx -2.1144\quad\text{and}\quad x\approx 2.0515

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